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Titanium is a transition metal - AQA - GCSE Chemistry - Question 8 - 2018 - Paper 1

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Titanium is a transition metal. Titanium is extracted from titanium dioxide in a two stage industrial process. Stage 1 TiO₂ + 2 C + 2 Cl₂ → TiCl₄ + 2 CO Stage 2 Ti... show full transcript

Worked Solution & Example Answer:Titanium is a transition metal - AQA - GCSE Chemistry - Question 8 - 2018 - Paper 1

Step 1

Suggest one hazard associated with Stage 1.

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Answer

One hazard associated with Stage 1 is that chlorine gas is toxic, posing a risk to health if inhaled.

Step 2

Give one reason why it would be hazardous if water came into contact with sodium.

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Answer

Water reacts vigorously with sodium, producing hydrogen gas, which is explosive and can cause fires.

Step 3

Suggest why the reaction in Stage 2 is carried out in an atmosphere of argon and not in air.

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Answer

The reaction is carried out in argon to prevent the formation of sodium hydroxide, which would occur if sodium reacted with moisture or oxygen in the air.

Step 4

Explain why you would not expect titanium chloride to be a liquid at room temperature.

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Answer

Titanium chloride is predominantly ionic, and ionic compounds typically have high melting points due to strong electrostatic forces between ions. Therefore, it may be expected to be a solid at room temperature.

Step 5

Why is this an oxidation reaction?

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Answer

This is an oxidation reaction because sodium atoms lose electrons to form sodium ions, which is a characteristic of oxidation.

Step 6

Complete the half equation for the oxidation reaction.

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Answer

Na → Na⁺ + e⁻

Step 7

Explain why titanium chloride is the limiting reactant.

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Answer

To calculate the moles of TiCl₄, we use the formula:

ext{Moles} = rac{ ext{mass}}{ ext{molar mass}}

The molar mass of TiCl₄ is 190 g/mol. For 40 kg (40000 g) of TiCl₄, the moles would be:

ext{Moles of TiCl₄} = rac{40000 g}{190 g/mol} = 210.53 ext{ mol}

For 20 kg of sodium, the moles would be:

ext{Moles of Na} = rac{20000 g}{23 g/mol} ext{ (approx. 870 mol)}

Hence, TiCl₄ is the limiting reactant as there aren’t enough moles of TiCl₄ to react with the amount of sodium provided.

Step 8

Calculate the actual mass of titanium produced.

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Answer

The actual mass of titanium produced can be calculated using the percentage yield:

ext{Actual mass} = rac{ ext{Percentage Yield}}{100} imes ext{Theoretical Mass}

Substituting the values:

ext{Actual mass} = rac{92.3}{100} imes 13.5 ext{ kg} = 12.46 ext{ kg}

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