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The camera in a mobile phone uses an LED to provide light when taking a photograph - AQA - GCSE Physics Combined Science - Question 5 - 2022 - Paper 1

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The camera in a mobile phone uses an LED to provide light when taking a photograph. A student investigated how the potential difference across an LED varies with th... show full transcript

Worked Solution & Example Answer:The camera in a mobile phone uses an LED to provide light when taking a photograph - AQA - GCSE Physics Combined Science - Question 5 - 2022 - Paper 1

Step 1

05.1 Explain how the student should have changed the circuit to make the LED emit light.

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Answer

The student should reverse the connections to the LED or battery. This is because an LED only allows current to flow in one direction, and reversing the connections will provide the correct potential difference to make it emit light.

Step 2

05.2 Calculate the potential difference across the LED.

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Answer

To find the potential difference (V) across the LED, use the formula: V=P/IV = P / I Where:

  • Power (P) = 0.98 W
  • Current (I) = 290 ext{ mA} = 0.290 ext{ A}

Substituting in the values: V = rac{0.98}{0.290} = 3.379 Rounded to two significant figures, the potential difference is 3.4 V.

Step 3

05.3 What happens when a xenon atom emits light?

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Answer

Electrons in the atom fall to a lower energy level.

Step 4

05.4 Calculate the mean current.

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Answer

Using the formula for current, where: Q=IimestQ = I imes t Rearranging gives: I = rac{Q}{t} To find charge (Q), use: Q=1.4extJ/200extV=0.007extCQ = 1.4 ext{ J} / 200 ext{ V} = 0.007 ext{ C} Now, substituting in the time (t = 2.8 × 10^−4 s): I = rac{0.007}{2.8 imes 10^{-4}} = 25 ext{ A} Therefore, the mean current is 25 A.

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