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The student connected an ammeter and a voltmeter into the circuit - AQA - GCSE Physics Combined Science - Question 1 - 2019 - Paper 1

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The student connected an ammeter and a voltmeter into the circuit. What is the correct way to connect the ammeter and the voltmeter into the circuit? Tick (✓) one ... show full transcript

Worked Solution & Example Answer:The student connected an ammeter and a voltmeter into the circuit - AQA - GCSE Physics Combined Science - Question 1 - 2019 - Paper 1

Step 1

The student connected an ammeter and a voltmeter into the circuit. What is the correct way to connect the ammeter and the voltmeter into the circuit?

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Answer

The ammeter should be connected in series with the resistor, and the voltmeter should be connected in parallel with the resistor. This configuration allows the ammeter to measure the current flowing through the resistor, while the voltmeter measures the potential difference across it.

Step 2

Increase the resistance of the variable resistor. How did increasing the resistance affect the current in the circuit?

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Answer

Increasing the resistance will decrease the current in the circuit. This is due to Ohm's law, which states that current is inversely proportional to resistance.

Step 3

How should the student change the circuit to give negative values for current and potential difference?

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Answer

To obtain negative values for current and potential difference, the connections to the cell should be reversed. This effectively reverses the polarity of the voltage supply.

Step 4

Name the type of relationship between current and potential difference for a resistor at constant temperature.

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Answer

The relationship between current and potential difference for a resistor at constant temperature is directly proportional.

Step 5

Write the equation which links current, potential difference and resistance.

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Answer

The equation that links current (I), potential difference (V), and resistance (R) is given by:

V=IimesRV = I imes R

Step 6

The current in the resistor was 0.12 A when the potential difference across the resistor was 3.0 V. Calculate the resistance of the resistor.

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Answer

Using Ohm's law, we rearrange the formula to find resistance:

R=VI=3.0 V0.12 A=25 ΩR = \frac{V}{I} = \frac{3.0 \text{ V}}{0.12 \text{ A}} = 25 \text{ }\Omega

Thus, the resistance of the resistor is 25 Ω.

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