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Figure 4 shows a sailing boat crossing an ocean - AQA - GCSE Physics Combined Science - Question 3 - 2021 - Paper 1

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Figure 4 shows a sailing boat crossing an ocean. There is a wind turbine on the boat. The wind turbine generates electricity to charge a battery on the boat. Name... show full transcript

Worked Solution & Example Answer:Figure 4 shows a sailing boat crossing an ocean - AQA - GCSE Physics Combined Science - Question 3 - 2021 - Paper 1

Step 1

Name one other renewable energy resource that could be used on the boat to generate electricity.

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Answer

One possible renewable energy resource that could be utilized is solar energy.

Step 2

Give two reasons why this is useful.

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Answer

  1. The generator can provide energy when there is no wind, ensuring continuous power availability.
  2. Utilizing both the wind turbine and the fossil fuel generator allows for a more reliable energy supply.

Step 3

Explain one environmental impact of using fossil fuels to generate electricity.

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Answer

One significant environmental impact of using fossil fuels is the emission of carbon dioxide (CO2), which contributes to global warming and the greenhouse effect.

Step 4

Calculate the speed of the boat.

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Answer

To find the speed of the boat, we can use the formula for kinetic energy:

KE=12mv2KE = \frac{1}{2}mv^2

Substituting the given values:

81000J=12×8000kg×v281 000 J = \frac{1}{2} \times 8000 kg \times v^2

Rearranging gives:

v2=81000J0.5×8000kgv4.5m/sv^2 = \frac{81 000 J}{0.5 \times 8000 kg} \Rightarrow v \approx 4.5 \, m/s

Step 5

Calculate the change in height of the centre of mass of the boat as it passes over the wave.

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Answer

To find the change in height (Δh\Delta h), we can use the potential energy formula:

PE=mghPE = mgh

Here, we have:

19600J=8000kg×9.8N/kg×Δh19 600 J = 8000 kg \times 9.8 N/kg \times \Delta h

Rearranging gives:

Δh=19600J8000kg×9.8N/kg0.25m\Delta h = \frac{19 600 J}{8000 kg \times 9.8 N/kg} \approx 0.25 \, m

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