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A student made measurements to determine the specific heat capacity of vegetable oil - AQA - GCSE Physics Combined Science - Question 2 - 2022 - Paper 1

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A student made measurements to determine the specific heat capacity of vegetable oil. Figure 2 shows the equipment used. Describe how the student could use the equ... show full transcript

Worked Solution & Example Answer:A student made measurements to determine the specific heat capacity of vegetable oil - AQA - GCSE Physics Combined Science - Question 2 - 2022 - Paper 1

Step 1

Describe how the student could use the equipment shown in Figure 2 to determine the specific heat capacity of vegetable oil.

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Answer

To determine the specific heat capacity of vegetable oil using the equipment shown in Figure 2, the student can follow these steps:

  1. Measure the mass of vegetable oil using the top pan balance and record it.
  2. Place the beaker containing the vegetable oil on the electric heater.
  3. Use the thermometer to monitor the initial temperature of the vegetable oil.
  4. Turn on the electric heater and allow the oil to heat for a specified amount of time.
  5. Measure the final temperature of the vegetable oil using the thermometer after heating.
  6. Use the recorded values of mass, temperature change, and energy transferred (which can be calculated using the power of the heater and the time it was on) to use the formula: c=EmΔTc = \frac{E}{m \Delta T} where cc is the specific heat capacity, EE is the energy transferred, mm is the mass of the oil, and riangleT riangle T is the change in temperature.

Step 2

Give one risk when using the equipment in Figure 2.

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Answer

One risk when using the equipment in Figure 2 is the potential for burns or scalds due to the hot oil or hot surfaces of the equipment.

Step 3

Write down the equation linking energy transferred (E), power (P) and time (t).

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Answer

The equation linking energy transferred (E), power (P), and time (t) is:
P=EtP = \frac{E}{t}
or rearranged,
E=P×tE = P \times t.

Step 4

Calculate the time taken for the electric element to transfer 4750 joules of energy to the vegetable oil.

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Answer

To calculate the time taken, use the formula:
E=P×tE = P \times t.
Given that E=4750E = 4750 joules and P=50P = 50 watts, we can rearrange the formula to find tt:
t=EP=475050=95st = \frac{E}{P} = \frac{4750}{50} = 95 \, \text{s}.

Step 5

What electrical component is used to monitor the temperature of the vegetable oil?

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Answer

The electrical component used to monitor the temperature of the vegetable oil is a thermistor.

Step 6

Determine the resistance of the electrical component when the electric heating element switched automatically off.

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Answer

Referring to Figure 3, if the oil temperature when the heating element switches off is 160 °C, the corresponding resistance from the graph is approximately 250 ohms.

Step 7

Why is this a physical change?

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Answer

This is a physical change because all water can change to steam without altering its chemical structure. The water will recover its original properties if the steam is cooled.

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