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A student determined the density of a cube made of bronze - AQA - GCSE Physics Combined Science - Question 4 - 2021 - Paper 1

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A student determined the density of a cube made of bronze. The student used a balance to measure the mass of the bronze cube. Figure 5 shows the balance before the ... show full transcript

Worked Solution & Example Answer:A student determined the density of a cube made of bronze - AQA - GCSE Physics Combined Science - Question 4 - 2021 - Paper 1

Step 1

What type of error is shown on the balance?

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Answer

The balance shows a zero error, indicated by the reading of 4.2 g before any mass is added.

Step 2

How could the student get a correct value for the mass of the cube from the balance?

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Answer

The student could reset the balance to zero grams before weighing the cube. This way, the reading will accurately reflect the mass of the cube.

Step 3

Complete the sentence.

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Answer

The results in Table 1 show that the Vernier callipers and the micrometer have a different resolution.

Step 4

Give two changes the student should make to increase the accuracy of the volume measurement.

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Answer

  1. Place the measuring cylinder on a horizontal surface to ensure a stable reading.
  2. View with eye in line with the level of the water to minimize parallax error.

Step 5

Describe how the student could use a displacement method to determine an accurate value for the volume of a single coin.

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Answer

The student could add several coins to the measuring cylinder filled with water. Then, measure the change in the water level in the measuring cylinder. Finally, divide the increase in water level by the number of coins added to find the volume of a single coin.

Step 6

Calculate value X in Table 2.

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Answer

To find X, first calculate the area:

Area=MassDensity=3.6g8.9g/cm30.4045cm2Area = \frac{Mass}{Density} = \frac{3.6g}{8.9g/cm^3} \approx 0.4045 \: cm^2

Using the volume formula:

Volume=Area×Thickness=0.4045cm2×0.17cm0.0688cm3Volume = Area \times Thickness = 0.4045 \: cm^2 \times 0.17 \: cm \approx 0.0688 \: cm^3

Now, calculate density for the new penny:

Density=MassVolume=3.6g0.0688cm352.48g/cm3Density = \frac{Mass}{Volume} = \frac{3.6g}{0.0688cm^3} \approx 52.48 \: g/cm^3

Therefore, value X in Table 2 is approximately 52.5 g/cm³ to two significant figures.

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