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A student investigated how the current in a filament lamp varied with the potential difference across the filament lamp - AQA - GCSE Physics - Question 1 - 2020 - Paper 1

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Question 1

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A student investigated how the current in a filament lamp varied with the potential difference across the filament lamp. Figure 1 shows part of the circuit used. C... show full transcript

Worked Solution & Example Answer:A student investigated how the current in a filament lamp varied with the potential difference across the filament lamp - AQA - GCSE Physics - Question 1 - 2020 - Paper 1

Step 1

Complete Figure 1 by adding an ammeter and a voltmeter.

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Answer

To complete Figure 1, add an ammeter in series with the filament lamp, and a voltmeter in parallel with the filament lamp. Use the correct circuit symbols:

  • Ammeter: A circle with 'A' inside it and a straight line representing the wire.
  • Voltmeter: A circle with 'V' inside it and two lines connecting across the filament lamp.

Step 2

Draw a line on Figure 2 to show the relationship between the negative values of current and potential difference.

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Answer

To show the relationship in Figure 2, draw a smooth, curved line that connects the negative values of potential difference and current. The line should reflect the trend, passing through points like (-4.0 V, -0.2 A) and (-6.0 V, -0.23 A). Ensure that the line does not become horizontal.

Step 3

Write down the equation which links current (I), potential difference (V) and resistance (R).

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Answer

The equation that links current (I), potential difference (V) and resistance (R) is given by:

V=I×RV = I \times R

Step 4

Determine the resistance of the filament lamp when the potential difference across it is 1.0 V.

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Answer

From Figure 2, when the potential difference, V = 1.0 V, the current, I = 0.08 A.

Using the equation:

R=VIR = \frac{V}{I}

Substituting the values:

R=1.0 V0.08 A=12.5ΩR = \frac{1.0 \text{ V}}{0.08 \text{ A}} = 12.5 \Omega

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