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A student investigated how the total resistance of identical resistors connected in series varied with the number of resistors - AQA - GCSE Physics - Question 4 - 2020 - Paper 1

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A student investigated how the total resistance of identical resistors connected in series varied with the number of resistors. The student used an ohmmeter to meas... show full transcript

Worked Solution & Example Answer:A student investigated how the total resistance of identical resistors connected in series varied with the number of resistors - AQA - GCSE Physics - Question 4 - 2020 - Paper 1

Step 1

Calculate the mean resistance of 1 resistor.

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Answer

To find the mean resistance of a single resistor, we use the total mean resistance of three resistors measured:

Rtotal=36.0extΩR_{total} = 36.0 ext{ Ω}

Since the resistors are identical, we divide the total resistance by the number of resistors:

R=Rtotaln=36.0extΩ3=12.0extΩR = \frac{R_{total}}{n} = \frac{36.0 ext{ Ω}}{3} = 12.0 ext{ Ω}

Thus, the mean resistance of one resistor is 12.0 Ω.

Step 2

What was the resolution of the ohmmeter the student used? Tick (✔) one box.

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Answer

The resolution of the ohmmeter used by the student was 0.1 Ω.

Step 3

How do the results show that the student’s measurements were precise? Tick (✔) one box.

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Answer

The results indicate that the measurements were precise because the measurements are grouped closely together.

Step 4

How do the results show that the total resistance is directly proportional to the number of resistors? Tick (✔) one box.

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Answer

The results show this relationship because the results give a straight line that would go through the origin.

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