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Electricity is generated when water from the reservoir flows through the turbines - AQA - GCSE Physics - Question 10 - 2020 - Paper 1

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Electricity is generated when water from the reservoir flows through the turbines. Write down the equation which links density (ρ), mass (m) and volume (V). 1 mar... show full transcript

Worked Solution & Example Answer:Electricity is generated when water from the reservoir flows through the turbines - AQA - GCSE Physics - Question 10 - 2020 - Paper 1

Step 1

Write down the equation which links density (ρ), mass (m) and volume (V).

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Answer

The equation that links density, mass, and volume is:

ho=mV ho = \frac{m}{V}

Step 2

Calculate the mass of water in the reservoir. Give your answer in standard form.

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Answer

To calculate the mass of water in the reservoir, use the equation:

m=ρ×Vm = \rho \times V

Substituting the provided values:

m=998kg/m3×6,500,000m3m = 998 \, \text{kg/m}^3 \times 6,500,000 \, \text{m}^3

Calculating:

m=6,487,000,000kgm = 6,487,000,000 \, \text{kg}

In standard form, this is:

m=6.487×109kgm = 6.487 \times 10^9 \, \text{kg}

Step 3

Write down the equation which links energy transferred (E), power (P) and time (t).

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Answer

The equation that links energy transferred, power, and time is:

E=P×tE = P \times t

Step 4

Calculate the maximum energy that can be transferred by the electrical generators.

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Answer

Given:

  • Power, P=1.5×106 WP = 1.5 \times 10^6 \text{ W}
  • Time, t=5exthours=5×60×60=18,000extst = 5 \, ext{hours} = 5 \times 60 \times 60 = 18,000 \, ext{s}

Calculating the maximum energy:

E=P×t=1.5×106×18,000=2.7×1010 JE = P \times t = 1.5 \times 10^6 \times 18,000 = 2.7 \times 10^{10} \text{ J}

Step 5

Give two reasons why this hydroelectric power station is not able to meet the increase in demand shown between 04:00 and 16:00 in Figure 15.

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Answer

  1. The variation in demand is much greater than the power output of the hydroelectric power station.
  2. The demand remains high for longer than 5 hours.

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