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Figure 2 shows the equipment a student used to determine the specific heat capacity of iron - AQA - GCSE Physics - Question 2 - 2023 - Paper 1

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Figure 2 shows the equipment a student used to determine the specific heat capacity of iron. The iron block the student used has two holes, one for the heater and o... show full transcript

Worked Solution & Example Answer:Figure 2 shows the equipment a student used to determine the specific heat capacity of iron - AQA - GCSE Physics - Question 2 - 2023 - Paper 1

Step 1

Suggest why the student left the thermometer in the iron block for a few minutes before recording the initial temperature.

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Answer

The student left the thermometer in the iron block for a few minutes to ensure that the thermometer temperature was the same as the temperature of the iron block. This allows for an accurate measurement of the initial temperature.

Step 2

Calculate the specific heat capacity of iron.

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Answer

To calculate the specific heat capacity, we first determine the change in temperature, Δθ=(5428)=26(°C) \Delta \theta = (54 - 28) = 26 \, (°C).

Using the formula for specific heat capacity, c=QmΔθc = \frac{Q}{m \Delta \theta}, where:

  • Q=26000JQ = 26000 \, J (energy transferred),
  • m=2.0kgm = 2.0 \, kg (mass of the iron block),
  • Δθ=26(°C) \Delta \theta = 26 \, (°C).

Substituting the values in:
c=260002.0×26=2600052=500(J/kg°C)c = \frac{26000}{2.0 \times 26} = \frac{26000}{52} = 500 \, (J/kg \, °C).

Thus, the specific heat capacity of iron is 500 J/kg °C.

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