Figure 6 shows the mass number and the atomic number for the nuclei of five different atoms - AQA - GCSE Physics - Question 6 - 2021 - Paper 1
Question 6
Figure 6 shows the mass number and the atomic number for the nuclei of five different atoms.
Figure 6
How many neutrons are there in a nucleus of atom A?
Which ... show full transcript
Worked Solution & Example Answer:Figure 6 shows the mass number and the atomic number for the nuclei of five different atoms - AQA - GCSE Physics - Question 6 - 2021 - Paper 1
Step 1
How many neutrons are there in a nucleus of atom A?
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To find the number of neutrons in atom A, we subtract the atomic number from the mass number. From Figure 6, atom A has a mass number of 234 and an atomic number of 86. Thus, the number of neutrons is calculated as follows:
Sign up now to view full answer, or log in if you already have an account!
Answer
In Figure 6, atoms D and E share the same atomic number, indicating they are the same element. Therefore, the correct answer is:
D and E
Step 3
Draw an arrow on Figure 7 to represent the alpha decay.
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Alpha decay in Nucleus B results in a decrease of the mass number by 4 and the atomic number by 2. Draw an arrow from atom B (mass number 232, atomic number 86) moving to the atom with mass number 228 (232-4) and atomic number 84 (86-2), representing the new nucleus formed after alpha decay.
Step 4
What is meant by the ‘random nature of radioactive decay’?
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The ‘random nature of radioactive decay’ refers to the unpredictability of when a particular nucleus will decay. While the average rate of decay (half-life) can be known for a sample, it is impossible to predict the exact moment when a specific nucleus will decay.
Step 5
Explain how these three decays result in a nucleus of the original element, polonium.
97%
117 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The decay process is as follows:
A polonium (Po) nucleus emits an alpha particle, which reduces its atomic number by 2 and its mass number by 4, resulting in lead (Pb).
The lead (Pb) nucleus then undergoes beta decay, where a neutron transforms into a proton, increasing the atomic number by 1 and keeping the mass number the same, resulting in bismuth (Bi).
Finally, the bismuth (Bi) nucleus emits another beta particle, again transforming a neutron into a proton. This results in the atomic number increasing by 1, leading back to a polonium (Po) nucleus.
Thus, the sequence of decays ultimately leads back to a nucleus of polonium: