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Figure 6 shows the mass number and the atomic number for the nuclei of five different atoms - AQA - GCSE Physics - Question 6 - 2021 - Paper 1

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Figure 6 shows the mass number and the atomic number for the nuclei of five different atoms. Figure 6 How many neutrons are there in a nucleus of atom A? Which ... show full transcript

Worked Solution & Example Answer:Figure 6 shows the mass number and the atomic number for the nuclei of five different atoms - AQA - GCSE Physics - Question 6 - 2021 - Paper 1

Step 1

How many neutrons are there in a nucleus of atom A?

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Answer

To find the number of neutrons in atom A, we subtract the atomic number from the mass number. From Figure 6, atom A has a mass number of 234 and an atomic number of 86. Thus, the number of neutrons is calculated as follows:

NumberofNeutrons=MassNumberAtomicNumber=23486=148.Number \: of \: Neutrons = Mass \: Number - Atomic \: Number = 234 - 86 = 148.

Step 2

Which two atoms in Figure 6 are the same element?

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Answer

In Figure 6, atoms D and E share the same atomic number, indicating they are the same element. Therefore, the correct answer is:

  • D and E

Step 3

Draw an arrow on Figure 7 to represent the alpha decay.

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Answer

Alpha decay in Nucleus B results in a decrease of the mass number by 4 and the atomic number by 2. Draw an arrow from atom B (mass number 232, atomic number 86) moving to the atom with mass number 228 (232-4) and atomic number 84 (86-2), representing the new nucleus formed after alpha decay.

Step 4

What is meant by the ‘random nature of radioactive decay’?

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The ‘random nature of radioactive decay’ refers to the unpredictability of when a particular nucleus will decay. While the average rate of decay (half-life) can be known for a sample, it is impossible to predict the exact moment when a specific nucleus will decay.

Step 5

Explain how these three decays result in a nucleus of the original element, polonium.

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Answer

The decay process is as follows:

  1. A polonium (Po) nucleus emits an alpha particle, which reduces its atomic number by 2 and its mass number by 4, resulting in lead (Pb).
  2. The lead (Pb) nucleus then undergoes beta decay, where a neutron transforms into a proton, increasing the atomic number by 1 and keeping the mass number the same, resulting in bismuth (Bi).
  3. Finally, the bismuth (Bi) nucleus emits another beta particle, again transforming a neutron into a proton. This results in the atomic number increasing by 1, leading back to a polonium (Po) nucleus.

Thus, the sequence of decays ultimately leads back to a nucleus of polonium:

PoightarrowPb+extαightarrowBi+extβightarrowPo+extβ.Po ightarrow Pb + ext{α} ightarrow Bi + ext{β} ightarrow Po + ext{β}.

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