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A student dropped a piece of modelling clay into oil - AQA - GCSE Physics - Question 1 - 2020 - Paper 1

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A student dropped a piece of modelling clay into oil. Figure 1 shows the modelling clay just before it was dropped into the oil. Figure 1 Modelling clay Oil Meas... show full transcript

Worked Solution & Example Answer:A student dropped a piece of modelling clay into oil - AQA - GCSE Physics - Question 1 - 2020 - Paper 1

Step 1

What was the distance fallen by the modelling clay?

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Answer

The distance fallen by the modelling clay is from B to C.

Step 2

Suggest one reason why.

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Answer

Each piece is removed to ensure that it falls freely without interference from other pieces, thus maintaining consistency in measurements.

Step 3

Calculate value X in Table 1.

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Answer

To find the mean time for the cylinder, sum the values of Drop 1, Drop 2, and Drop 3: X=34+37+343=1053=35(s)X = \frac{34 + 37 + 34}{3} = \frac{105}{3} = 35 (s)

Step 4

Which shape in Table 1 had the smallest resistive force acting against it as it fell?

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Answer

Cone Reason: The cone had the lowest mean time, indicating it faced the least resistive force.

Step 5

How would the time taken to fall change if the modelling clay was dropped through air instead of through oil?

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Answer

Time through air would be more.

Step 6

Calculate the weight of the piece of modelling clay.

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Answer

The weight can be calculated using the formula: weight=mass×gravitational field strength=0.050 kg×9.8 N/kg=0.49 N\text{weight} = \text{mass} \times \text{gravitational field strength} = 0.050 \text{ kg} \times 9.8 \text{ N/kg} = 0.49 \text{ N}

Step 7

Which of the following are also non-contact forces?

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Answer

Tick both:

  • Electrostatic force
  • Air resistance

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