Photo AI

The remote control transmits radio waves to the car aerial - AQA - GCSE Physics - Question 6 - 2020 - Paper 1

Question icon

Question 6

The-remote-control-transmits-radio-waves-to-the-car-aerial-AQA-GCSE Physics-Question 6-2020-Paper 1.png

The remote control transmits radio waves to the car aerial. The transmitted radio waves have a frequency of 320 MHz. speed of radio waves = 3.0 × 10^8 m/s Calcula... show full transcript

Worked Solution & Example Answer:The remote control transmits radio waves to the car aerial - AQA - GCSE Physics - Question 6 - 2020 - Paper 1

Step 1

Calculate the wavelength of the radio waves.

96%

114 rated

Answer

To find the wavelength (λ\lambda), we use the formula:

λ=vf\lambda = \frac{v}{f}

Where:

  • vv is the speed of the radio waves = 3.0×1083.0 \times 10^8 m/s
  • ff is the frequency = 320320 MHz = 320×106320 \times 10^6 Hz.

Substituting the values, we have:

λ=3.0×108320×106=0.9375 m\lambda = \frac{3.0 \times 10^8}{320 \times 10^6} = 0.9375 \text{ m}

Thus, the wavelength of the radio waves is approximately 0.940.94 m.

Step 2

Describe what happens in the electrical circuit when the car aerial absorbs radio waves.

99%

104 rated

Answer

When the car aerial absorbs radio waves, an alternating current is induced in the electrical circuit. This current oscillates with the same frequency as the radio waves, allowing the circuit to process the signals.

Step 3

Give two ways in which radio waves are different from sound waves.

96%

101 rated

Answer

  1. Radio waves are transverse waves, while sound waves are longitudinal waves.
  2. Radio waves travel at the speed of light, while sound waves travel through a medium and are much slower.

Step 4

Describe the motion of the car during the first 30 seconds.

98%

120 rated

Answer

The car is accelerating continuously during the first 30 seconds.

Step 5

Determine the speed of the car 20 seconds after it started to move.

97%

117 rated

Answer

To find the speed (vv) after 20 seconds, we can use the average speed formula if acceleration is constant. Assuming constant acceleration of 0.280.28 m/s² from earlier calculations, we get:

v=u+atv = u + at With initial speed (uu) = 0 m/s: v=0+(0.28m/s2)(20s)=5.6m/sv = 0 + (0.28 m/s²)(20 s) = 5.6 \, m/s

Thus, the speed of the car after 20 seconds is 5.6 m/s.

Step 6

Calculate the resultant force needed to accelerate the car.

97%

121 rated

Answer

Using Newton's second law, the resultant force (FF) can be calculated using:

F=maF = ma

First, calculate mass (mm) given:

  • Initial speed (uu) = 0.12 m/s
  • Final speed (vv) = 0.52 m/s
  • Acceleration (aa) = 0.040 m/s²

Work done (WW) is given as 0.48 J, so:

Using the work-energy principle: W=FdW = F \cdot d

displacement (dd) can be calculated: d(0.12+0.52)2t=0.64m/s210s=3.2m    F=0.48J3.2m=0.15 Nd \approx \frac{(0.12 + 0.52)}{2} \cdot t = \frac{0.64 m/s}{2} \cdot 10 s = 3.2 m \implies F = \frac{0.48 J}{3.2 m} = 0.15 \text{ N}

Thus, the resultant force needed is 0.15 N.

Step 7

Explain why the car has a maximum speed.

96%

114 rated

Answer

The car has a maximum speed because the driving force provided by the motor is balanced by the resistance forces such as air resistance. As the car accelerates, these resisting forces increase until they equal the driving force, at which point the car can no longer accelerate and travels at its maximum speed (terminal velocity).

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;