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The remote control transmits radio waves to the car aerial - AQA - GCSE Physics - Question 6 - 2020 - Paper 1

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The remote control transmits radio waves to the car aerial. The transmitted radio waves have a frequency of 320 MHz. speed of radio waves = 3.0 × 10^8 m/s Calcula... show full transcript

Worked Solution & Example Answer:The remote control transmits radio waves to the car aerial - AQA - GCSE Physics - Question 6 - 2020 - Paper 1

Step 1

Calculate the Wavelength

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Answer

To find the wavelength ( ( \lambda ) ), we can use the formula:

λ=vf\lambda = \frac{v}{f}

where:

  • ( v ) = speed of the waves = ( 3.0 \times 10^8 ) m/s
  • ( f ) = frequency = ( 320 ) MHz = ( 320 \times 10^6 ) Hz

Substituting the values in, we get:

λ=3.0×108320×106=0.9375m\lambda = \frac{3.0 \times 10^8}{320 \times 10^6} = 0.9375 \, \text{m}

Thus, the wavelength of the radio waves is approximately ( 0.94 , \text{m} ).

Step 2

Describe What Happens in the Electrical Circuit

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Answer

When the car aerial absorbs the radio waves:

  1. An alternating current is induced in the electrical circuit, resulting from the oscillation of the electric and magnetic fields present in the radio wave.
  2. The electrons in the circuit vibrate or oscillate with the same frequency as the incoming radio waves.

Step 3

Give Two Ways Radio Waves Are Different From Sound Waves

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Answer

  1. Radio waves are electromagnetic waves, while sound waves are mechanical waves.
  2. Radio waves can travel through a vacuum, whereas sound waves require a medium (such as air or water) to propagate.

Step 4

Describe the Motion of the Car During the First 30 Seconds

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Answer

The car is accelerating during the first 30 seconds of motion.

Step 5

Determine the Speed of the Car 20 Seconds After It Started to Move

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Answer

To find the speed ( ( v ) ) of the car after 20 seconds, we can use the relationship:

  1. The initial speed is assumed 0, and using the previously given values, we find:
    • Speed after 20 seconds, if a certain acceleration is assumed (e.g., 0.28 m/s as calculated from a graph), will be used here: v=0.28×20=5.6m/sv = 0.28 \times 20 = 5.6 \, \text{m/s} Hence, the speed of the car is ( 5.6 , \text{m/s} ).

Step 6

Calculate the Resultant Force Needed to Accelerate the Car

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Answer

The resultant force ( ( F ) ) can be calculated using Newton's second law:

F=maF = m \cdot a

where:

  • The mass of the car (assumed from work-energy principle or other context as needed)
  • The acceleration = ( 0.040 , \text{m/s}^2 )

Using work done = 0.48 J, and displacement as calculated:

  • Rearranging, we can find:
F=0.483.2=0.15NF = \frac{0.48}{3.2} = 0.15 \, \text{N}

Step 7

Explain Why the Car Has a Maximum Speed

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Answer

The car reaches a maximum speed when:

  1. The driving force provided by the motor equals the resistive forces acting against it (like friction and air resistance).
  2. As speed increases, air resistance increases, making it harder for the car to accelerate further.
  3. Eventually, resistive forces balance the driving force, causing the car to travel at a constant speed, known as terminal velocity.

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