Identify the parts of the transformer labelled in Figure 12 - AQA - GCSE Physics - Question 7 - 2022 - Paper 1

Using the transformer equation: $\frac{V_s}{V_p} = \frac{N_s}{N_p}$ Letting the number of turns in the secondary coil be 1200 turns, we can write: $\frac{1200}{230} = \frac{V_s}{230}$ Solving for $V_s$ gives: $V_s = 1380 \text{ V}$

The alternating current causes a changing magnetic field around the primary coil. This creates a magnetic field that changes direction in the core, inducing an alternating potential difference across the secondary coil, resulting in an alternating current.

The direction of the force is down.

Using the formula: $F = B I L$ Substituting the known values: $0.045 = 60 \times 10^{-6} \times 50 \times L$ Rearranging gives: $L = \frac{0.045}{60 \times 10^{-6} \times 50} = 15 \text{ m}$

The wire/force is at right angles to the magnetic field.