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Question 3
Humans produce hormones to control reproductive cycles and to control urine production. (a) After fertilisation an embryo is implanted in the lining of the uterus. ... show full transcript
Step 1
Answer
The sex of the embryo is determined by the combination of sex chromosomes contributed by the parents during fertilisation. Males contribute either an X or a Y chromosome from the sperm, while females provide an X chromosome from the egg. If the sperm carries an X chromosome, the resulting genotype will be XX, leading to a female embryo. Conversely, if the sperm carries a Y chromosome, the genotype will be XY, resulting in a male embryo.
Step 2
Step 3
Answer
To calculate the probability using the Punnett square, we represent the female carrier with genotype X^H X^h and the non-haemophiliac male with genotype X^H Y.
The Punnett square will look like this:
| X^H | Y
------------------
X^H | X^H X^H | X^H Y
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X^h | X^H X^h | X^h Y
The possible genotypes for their children are:
From this, there are two males (X^H Y and X^h Y) and out of the four offspring, one (X^h Y) is a male with haemophilia. Thus, the probability of having a male child with haemophilia is:
P(X^h Y) = rac{1}{4}
This can also be expressed as 25%.
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