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(a) DNA is composed of four different DNA nucleotides - Edexcel - GCSE Biology - Question 7 - 2016 - Paper 1

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(a) DNA is composed of four different DNA nucleotides. (i) Which diagram represents the arrangement of the sugar, phosphate and the base in a DNA nucleotide? (ii) ... show full transcript

Worked Solution & Example Answer:(a) DNA is composed of four different DNA nucleotides - Edexcel - GCSE Biology - Question 7 - 2016 - Paper 1

Step 1

Which diagram represents the arrangement of the sugar, phosphate and the base in a DNA nucleotide?

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Answer

The correct diagram representing the arrangement of the sugar, phosphate, and base in a DNA nucleotide is option C. The key indicates that the sugar is represented by a pentagon, the phosphate by a circle, and the base by a rectangle.

Step 2

An allele starts with the DNA sequence ATGCATGTACCG. Give the sequence of the complementary DNA sequence.

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Answer

The complementary DNA sequence for ATGCATGTACCG is TACGTACAUGGC, where each base pairs with its complement: A with T, and C with G.

Step 3

The length of one DNA nucleotide was measured at 3.3 × 10^-10 metres. Calculate the approximate length of a gene containing 250 nucleotides in nanometres.

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Answer

To calculate the length of a gene with 250 nucleotides:

  1. Convert the length of one nucleotide from metres to nanometres: 1 metre = 1 imes 10^9 nanometres, hence: Length of one nucleotide = 3.3 imes 10^{-10} ext{ m} = 3.3 imes 10^{-10} imes 1 imes 10^9 ext{ nm} = 0.33 ext{ nm}.

  2. Therefore, the length of a gene with 250 nucleotides: Length = 250 imes 0.33 ext{ nm} = 82.5 ext{ nm}.

Step 4

State the genotype of Rani:

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Answer

Rani must be heterozygous for the fur pigmentation trait, as she produced offspring with white fur (recessive). Therefore, her genotype is A/a, where A is for normal pigmentation and a is for white fur.

Step 5

The offspring with normal fur pigmentation was bred with a tiger that was heterozygous. Use A/a to represent the alleles for fur pigmentation. Predict, using the Punnett square, the percentage probability of the offspring from this cross having normal fur pigmentation.

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Answer

Using a Punnett square:

Aa
AAAAa
aAaaa

From the Punnett square, there are 3 combinations that lead to normal pigmentation (AA, Aa) out of 4 total combinations.

Hence, the percentage probability of the offspring having normal fur pigmentation is:

rac{3}{4} imes 100 = 75 ext{ %}.

Step 6

Explain how two parents with a dominant phenotype can produce offspring expressing a recessive characteristic.

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Two parents displaying a dominant phenotype can produce offspring showing a recessive phenotype if both parents are heterozygous for the trait. For example, if both parents have the genotype A/a, they can pass on the recessive allele 'a' to their offspring. The combinations (AA, Aa, Aa, aa) from the Punnett square indicate that there is a 25% chance of producing an offspring with the genotype 'aa', resulting in the recessive phenotype.

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