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This question is about properties of materials - Edexcel - GCSE Chemistry Combined Science - Question 7 - 2016 - Paper 1

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This question is about properties of materials. (a) Figure 6 shows some properties of steel and Kevlar®: | property | steel | Kevlar® | |----------... show full transcript

Worked Solution & Example Answer:This question is about properties of materials - Edexcel - GCSE Chemistry Combined Science - Question 7 - 2016 - Paper 1

Step 1

Calculate the surface area to volume ratio of this cube of silver.

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Answer

To calculate the surface area to volume ratio of a cube, we can use the following formulas:

  1. Surface Area (SA) of a cube with side length s:

    SA=6s2SA = 6s^2

  2. Volume (V) of a cube with side length s:

    V=s3V = s^3

Given that the length of one side of the cube is 2 cm:

  • Surface Area:

    SA=6(2)2=6×4=24 cm2SA = 6(2)^2 = 6 \times 4 = 24 \text{ cm}^2

  • Volume:

    V=(2)3=8 cm3V = (2)^3 = 8 \text{ cm}^3

  1. Surface Area to Volume Ratio (SA:V):

    SA:V=SAV=24 cm28 cm3=3 cm1\text{SA:V} = \frac{SA}{V} = \frac{24 \text{ cm}^2}{8 \text{ cm}^3} = 3 \text{ cm}^{-1}

Thus, the surface area to volume ratio is 3 cm⁻¹.

Step 2

Suggest an explanation of why a given mass of silver is more effective as a catalyst when used as nanoparticles rather than in powder form.

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Answer

Nanoparticles of silver have a significantly larger surface area relative to their volume compared to larger particles in powder form. This increased surface area enhances the number of active sites available for reactions. Therefore, for the same mass, there are more particles exposed that can react, leading to a higher probability of effective collisions with reactants. This results in an increased rate of reaction, making silver nanoparticles a more effective catalyst.

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