Photo AI

In Figure 5, the letters A, E, G, J, X and Z show the positions of six elements in the periodic table - Edexcel - GCSE Chemistry Combined Science - Question 5 - 2019 - Paper 1

Question icon

Question 5

In-Figure-5,-the-letters-A,-E,-G,-J,-X-and-Z-show-the-positions-of-six-elements-in-the-periodic-table-Edexcel-GCSE Chemistry Combined Science-Question 5-2019-Paper 1.png

In Figure 5, the letters A, E, G, J, X and Z show the positions of six elements in the periodic table. These letters are not the symbols of the atoms of these eleme... show full transcript

Worked Solution & Example Answer:In Figure 5, the letters A, E, G, J, X and Z show the positions of six elements in the periodic table - Edexcel - GCSE Chemistry Combined Science - Question 5 - 2019 - Paper 1

Step 1

Using the letters A, E, G, J and Z (i) give the letters of the two elements that are non-metals.

96%

114 rated

Answer

The non-metals in this arrangement are E and G.

Step 2

Using the letters A, E, G, J and Z (ii) give the letters of two elements in period 2.

99%

104 rated

Answer

The two elements in period 2 are E and J.

Step 3

Using the letters A, E, G, J and Z (iii) give the letter of an element that normally forms an ion with a charge of +1.

96%

101 rated

Answer

The element that normally forms an ion with a charge of +1 is J.

Step 4

All atoms of element E in this sample contain (iv) A 5 protons B 5 neutrons C 6 protons D 6 neutrons.

98%

120 rated

Answer

The correct answer is A: 5 protons.

Step 5

Element X has an atomic number of 18. State the electronic configuration of an atom of element X.

97%

117 rated

Answer

The electronic configuration of element X is 2.8.8.

Step 6

In an experiment, 3.5 g of element A reacted with 4.0 g of element G to form a compound. Calculate the empirical formula of this compound.

97%

121 rated

Answer

To find the empirical formula, first calculate the moles of each element:

For element A: extMolesofA=3.5extg7extg/mol=0.5extmoles ext{Moles of A} = \frac{3.5 ext{ g}}{7 ext{ g/mol}} = 0.5 ext{ moles}

For element G: extMolesofG=4.0extg16extg/mol=0.25extmoles ext{Moles of G} = \frac{4.0 ext{ g}}{16 ext{ g/mol}} = 0.25 ext{ moles}

Now divide each by the smallest number of moles:

For A: 0.50.25=2\frac{0.5}{0.25} = 2

For G: 0.250.25=1\frac{0.25}{0.25} = 1

Therefore, the empirical formula is A₂G.

Step 7

An oxygen atom has six electrons in its outer shell. A hydrogen atom has one electron in its outer shell. Complete the dot and cross diagram of a molecule of water, H₂O. Show outer shell electrons only.

96%

114 rated

Answer

In the dot and cross diagram for water (H₂O), indicate that oxygen shares its six outer shell electrons with two hydrogen atoms, each contributing one electron:

  • Represent oxygen's electrons with dots and hydrogen's electrons with crosses.
  • The diagram would illustrate two overlaps between the oxygen and the hydrogen atoms for the bonds.

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;