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This question is about potassium and zinc - Edexcel - GCSE Chemistry Combined Science - Question 3 - 2021 - Paper 1

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This question is about potassium and zinc. (a) Which of the following temperatures is most likely to be the melting point of potassium? ☐ A -63°C ☐ B 6.3°C ☐ C 63°... show full transcript

Worked Solution & Example Answer:This question is about potassium and zinc - Edexcel - GCSE Chemistry Combined Science - Question 3 - 2021 - Paper 1

Step 1

Which of the following temperatures is most likely to be the melting point of potassium?

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Answer

The melting point of potassium is most likely to be 63°C (C). This is because potassium is an alkali metal, which typically have low melting points. Among the given options, -63°C would make potassium a gas at room temperature, while 6.3°C and 630°C are not representative of potassium's melting point.

Step 2

Explain how the electronic configuration of an atom of potassium is related to its position in the periodic table.

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Answer

Potassium (K) has the atomic number 19, which means it has 19 electrons. Its electronic configuration is 1s² 2s² 2p⁶ 3s¹. Potassium is located in Group 1 of the periodic table, which consists of alkali metals. The single electron in the outermost shell (3s¹) determines its chemical reactivity and its position. As you move down Group 1, the reactivity increases due to the increasing atomic size and decreasing ionization energy.

Step 3

Describe the test to show that a gas is oxygen.

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To test for oxygen, you can use a glowing splint. If a glowing splint is inserted into a container of a gas and it relights, then the gas is oxygen. This reaction occurs because oxygen supports combustion.

Step 4

Write the electronic configurations for the ions in potassium oxide, K₂O.

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Answer

In potassium oxide (K₂O), potassium forms K⁺ ions. The electronic configuration for K⁺ is 1s² 2s² 2p⁶. Oxygen (O) in K₂O forms O²⁻ ions, and its electronic configuration is 1s² 2s² 2p⁶ 3s² 3p⁴. When it gains two electrons to achieve its stable electronic configuration, it becomes O²⁻ with the configuration 1s² 2s² 2p⁶.

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