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Magnesium carbonate has the formula MgCO<sub>3</sub> - Edexcel - GCSE Chemistry Combined Science - Question 6 - 2022 - Paper 1

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Magnesium carbonate has the formula MgCO<sub>3</sub>. (a) Magnesium carbonate contains Mg<sup>2+</sup> and CO<sub>3</sub><sup>2-</sup> ions. (i) The atomic number ... show full transcript

Worked Solution & Example Answer:Magnesium carbonate has the formula MgCO<sub>3</sub> - Edexcel - GCSE Chemistry Combined Science - Question 6 - 2022 - Paper 1

Step 1

What is the electronic configuration of the Mg<sup>2+</sup> ion?

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Answer

The electronic configuration of the Mg<sup>2+</sup> ion is 2. This is because magnesium has an atomic number of 12, indicating it has 12 electrons. When it loses two electrons to form Mg<sup>2+</sup>, it has 10 electrons remaining, which are arranged as 2 in the first shell and 8 in the second shell.

Step 2

Explain why solid magnesium carbonate cannot conduct electricity but solid magnesium can.

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Answer

Solid magnesium carbonate cannot conduct electricity because it is an ionic compound. In the solid state, the ions are held in a fixed position within a crystal lattice and cannot move freely. Therefore, there are no mobile charge carriers to allow the flow of electricity. In contrast, solid magnesium is a metal and contains delocalized electrons that are free to move within the metal structure. This allows solid magnesium to conduct electricity effectively.

Step 3

Calculate the percentage by mass of magnesium in magnesium carbonate, MgCO<sub>3</sub>.

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To calculate the percentage by mass of magnesium in magnesium carbonate (MgCO<sub>3</sub>), we first determine the molar mass of MgCO<sub>3</sub>:

  • Molar mass of Mg = 24.0 g/mol
  • Molar mass of C = 12.0 g/mol
  • Molar mass of O = 16.0 g/mol × 3 = 48.0 g/mol
  • Total molar mass of MgCO<sub>3</sub> = 24.0 + 12.0 + 48.0 = 84.0 g/mol

Now, we find the percentage by mass of magnesium:

extPercentagebymassofmagnesium=(mass of Mgtotal mass of MgCO3)×100 ext{Percentage by mass of magnesium} = \left( \frac{\text{mass of Mg}}{\text{total mass of MgCO}_3} \right) \times 100

=(24.084.0)×10028.57%= \left( \frac{24.0}{84.0} \right) \times 100 \approx 28.57\%

Thus, the percentage by mass of magnesium in magnesium carbonate is approximately 28.57%.

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