A student used the apparatus in Figure 1 to investigate the rate of the reaction between a metal and dilute hydrochloric acid. Pieces of the metal were placed in dilute hydrochloric acid in the flask, and the total volume of gas produced was measured every minute. Figure 2 shows a graph of the student’s results. Volume of hydrogen in cm³ Time in minutes Figure 2

GCSE Edexcel Chemistry Combined Science Reactions of acids: A student used the apparatus in

A student used the apparatus in Figure 1 to investigate the rate of the reaction between a metal and dilute hydrochloric acid - Edexcel - GCSE Chemistry Combined Science - Question 1 - 2022 - Paper 1

Question 1

A-student-used-the-apparatus-in-Figure-1-to-investigate-the-rate-of-the-reaction-between-a-metal-and-dilute-hydrochloric-acid-Edexcel-GCSE Chemistry Combined Science-Question 1-2022-Paper 1.png

A student used the apparatus in Figure 1 to investigate the rate of the reaction between a metal and dilute hydrochloric acid. Pieces of the metal were placed in di... show full transcript

Worked Solution & Example Answer:A student used the apparatus in Figure 1 to investigate the rate of the reaction between a metal and dilute hydrochloric acid - Edexcel - GCSE Chemistry Combined Science - Question 1 - 2022 - Paper 1

Step 1

1(i) What measuring cylinder could they have used? Why?

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Answer

The student could have used a 100 cm³ measuring cylinder for their experiment. This is because it provides a suitable maximum volume for the possible gas produced and has smaller graduations, which allows for more precise measurements of the volume of hydrogen gas collected.

Step 2

1(ii) Calculate the rate of reaction at 90 seconds. Show your working.

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Answer

To calculate the rate of reaction at 90 seconds:

From the graph in Figure 2, determine the volume of hydrogen produced at 90 seconds. Let's assume that is 29 cm³.
The rate of reaction can be calculated using the formula:

$\text{Rate} = \frac{\text{Volume}}{\text{Time}}$
Substituting the values we get:

$\text{Rate} = \frac{29 \text{ cm}^3}{90 \text{ seconds}}$ $\text{Rate} \approx 0.322{2} \text{ cm}^3/\text{second}$

Thus, the rate of reaction at 90 seconds is approximately 0.322 cm³ per second.

A student used the apparatus in Figure 1 to investigate the rate of the reaction between a metal and dilute hydrochloric acid - Edexcel - GCSE Chemistry Combined Science - Question 1 - 2022 - Paper 1

Worked Solution & Example Answer:A student used the apparatus in Figure 1 to investigate the rate of the reaction between a metal and dilute hydrochloric acid - Edexcel - GCSE Chemistry Combined Science - Question 1 - 2022 - Paper 1

1(i) What measuring cylinder could they have used? Why?

1(ii) Calculate the rate of reaction at 90 seconds. Show your working.

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