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Most of the fuels used today are obtained from crude oil - Edexcel - GCSE Chemistry Combined Science - Question 1 - 2019 - Paper 1

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Most of the fuels used today are obtained from crude oil. (a) Which statement about crude oil is correct? A crude oil is a compound of different hydrocarbons B ... show full transcript

Worked Solution & Example Answer:Most of the fuels used today are obtained from crude oil - Edexcel - GCSE Chemistry Combined Science - Question 1 - 2019 - Paper 1

Step 1

Which statement about crude oil is correct?

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Answer

The correct answer is B: crude oil is a mixture of hydrocarbons. This statement accurately reflects the nature of crude oil, which is primarily composed of various hydrocarbons that can be separated through processes like fractional distillation.

Step 2

State a use for each of these fractions.

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Answer

Kerosene is commonly used as a fuel for jet engines and heating, while diesel oil is used as fuel for diesel engines in vehicles and machinery.

Step 3

Choose a property. Compare how this property for kerosene compares with the property for diesel oil.

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A property that can be compared is the boiling point. Kerosene has a lower boiling point than diesel oil, which is why kerosene is collected higher up in the fractionating column during fractional distillation.

Step 4

Explain, using these formulae, why butane and pentane are neighbouring members of the same homologous series.

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Answer

Butane (C4H10) and pentane (C5H12) are neighbouring members of the alkane series because they differ by one -CH2- group. This difference in one carbon atom and two hydrogen atoms indicates that they are part of a continuous series where each successive compound has similar chemical properties.

Step 5

Calculate the mass of carbon in 100 g of butane.

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Answer

To find the mass of carbon in 100 g of butane (C4H10):

  1. Calculate the molar mass of butane:

    ext{Molar mass} = (4 imes 12.0) + (10 imes 1.00) = 58.0 ext{ g/mol}

  2. Find the fraction of the mass of carbon in butane:

    rac{(4 imes 12.0)}{58.0} = 0.8276 ext{ (dimensionless)}

  3. Multiply by the total mass:

    0.8276 imes 100 g = 82.76 g

Thus, the mass of carbon in 100 g of butane is approximately 82.8 g.

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