1
Most of the fuels used today are obtained from crude oil - Edexcel - GCSE Chemistry Combined Science - Question 1 - 2019 - Paper 1
Question 1
1
Most of the fuels used today are obtained from crude oil.
(a) Which statement about crude oil is correct?
1 A crude oil is a compound of different hydrocar... show full transcript
Worked Solution & Example Answer:1
Most of the fuels used today are obtained from crude oil - Edexcel - GCSE Chemistry Combined Science - Question 1 - 2019 - Paper 1
Step 1
Which statement about crude oil is correct?
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The correct statement is that crude oil is a mixture of hydrocarbons (Option B). Crude oil is not a single compound but a complex mixture of various hydrocarbons that can vary in composition.
Step 2
State a use for each of these fractions.
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Kerosene is commonly used as a fuel for jet engines in aviation, while diesel oil is primarily used in diesel engines for vehicles.
Step 3
Choose a property.
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
A property to compare is the boiling point. Kerosene has a lower boiling point than diesel oil, which is why it is collected higher in the fractionating column.
Step 4
Explain, using these formulae, why butane and pentane are neighbouring members of the same homologous series.
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Butane (C₄H₁₀) and pentane (C₅H₁₂) are neighbouring members of the homologous series of alkanes. They differ by the addition of one methylene (-CH₂-) group, which gives them similar chemical properties while maintaining a distinct formula. Each subsequent member of this series increases by the same amount, providing a systematic relationship in their structural formulas.
Step 5
Calculate the mass of carbon in 100g of butane.
97%
117 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To calculate the mass of carbon in 100g of butane (C₄H₁₀), first determine its molar mass:
Molar mass of butane = 4 × 12.0 (for C) + 10 × 1.00 (for H) = 58.0 g/mol
Now, calculate the mass of carbon:
Mass of carbon in 1 mole of butane = 4 × 12.0 = 48.0 g
In 100g of butane, the mass of carbon is:
rac{48.0 ext{ g}}{58.0 ext{ g/mol}} imes 100 ext{ g} \\ = 82.76 ext{ g}
Rounding to three significant figures gives the mass of carbon as 82.8 g.