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A student wanted to find the volume of dilute hydrochloric acid that would react with 25.0 cm³ of lithium hydroxide solution - Edexcel - GCSE Chemistry - Question 4 - 2022 - Paper 1

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A student wanted to find the volume of dilute hydrochloric acid that would react with 25.0 cm³ of lithium hydroxide solution. They used the equipment in Figure 7 to... show full transcript

Worked Solution & Example Answer:A student wanted to find the volume of dilute hydrochloric acid that would react with 25.0 cm³ of lithium hydroxide solution - Edexcel - GCSE Chemistry - Question 4 - 2022 - Paper 1

Step 1

Suggest why the student carried out a rough titration before the two accurate titrations.

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Answer

The student carried out a rough titration to obtain an approximate indication of the volume of dilute hydrochloric acid needed to react completely with the lithium hydroxide solution. This initial rough titration helps to refine the approach for the subsequent accurate titrations, allowing the student to better estimate the required volume and minimize overshooting the endpoint.

Step 2

What was the volume of acid added in the rough titration?

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Answer

To calculate the volume of hydrochloric acid added during the rough titration, subtract the initial reading from the final reading on the burette:

extVolumeofacid=extFinalreadingextInitialreading=30.10extcm32.50extcm3=27.60extcm3 ext{Volume of acid} = ext{Final reading} - ext{Initial reading} = 30.10 ext{ cm}^3 - 2.50 ext{ cm}^3 = 27.60 ext{ cm}^3

Therefore, the volume of acid added in the rough titration was 27.60 cm³.

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