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Hydrogen burns in air at a temperature well above 100 °C to form water - Edexcel - GCSE Chemistry - Question 4 - 2018 - Paper 1

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Hydrogen burns in air at a temperature well above 100 °C to form water. (i) The boiling points of hydrogen and water are shown in Figure 3. Use this information to... show full transcript

Worked Solution & Example Answer:Hydrogen burns in air at a temperature well above 100 °C to form water - Edexcel - GCSE Chemistry - Question 4 - 2018 - Paper 1

Step 1

Add the missing state symbols to the equation for the reaction taking place as the hydrogen burns.

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Answer

The correct equation with state symbols is:

2H2(g)+O2(g)ightarrow2H2O(l)2H_{2}(g) + O_{2}(g) ightarrow 2H_{2}O(l)

In this equation, hydrogen is in the gaseous state (g) and water is in the liquid state (l), considering the temperature is above 100 °C.

Step 2

State how the equation shows that the atom economy is 100%.

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Answer

The equation shows that the atom economy is 100% because all the reactants (hydrogen and oxygen) are converted into the desired product (water) without producing any by-products. Therefore, there are no waste products, indicating complete conversion of reactants.

Step 3

Calculate the atom economy for the production of lead in this reaction.

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Answer

To calculate the atom economy, we first need to determine the molar masses and then apply the formula for atom economy:

  1. Calculate the total mass of reactants:

    • Molar mass of 2PbO = 2 x 223 = 446 g
    • Molar mass of C = 12 g
    • Total mass of reactants = 446 g + 12 g = 458 g
  2. Calculate the mass of useful products:

    • Molar mass of 2Pb = 2 x 207 = 414 g
  3. Apply atom economy formula:

ext{Atom Economy} = rac{ ext{Mass of Useful Products}}{ ext{Total Mass of Reactants}} imes 100 ext{Atom Economy} = rac{414}{458} imes 100 \\ ext{Atom Economy} = 90.39 ext{%} ext{ (to 2 significant figures: 90 ext{%})}

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