5. Fluorine, chlorine, bromine and iodine are elements in group 7 of the periodic table - Edexcel - GCSE Chemistry - Question 5 - 2021 - Paper 1
Question 5
5. Fluorine, chlorine, bromine and iodine are elements in group 7 of the periodic table.
(a) (i) State the name given to the group 7 elements.
(ii) Name one other ... show full transcript
Worked Solution & Example Answer:5. Fluorine, chlorine, bromine and iodine are elements in group 7 of the periodic table - Edexcel - GCSE Chemistry - Question 5 - 2021 - Paper 1
Step 1
State the name given to the group 7 elements.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The name given to the Group 7 elements is halogens.
Step 2
Name one other element that is in group 7.
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
One other element that is in Group 7 is astatine.
Step 3
Which element is liquid at room temperature and pressure?
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The element that is liquid at room temperature and pressure is C. bromine.
Step 4
Which element is dark-grey in colour at room temperature and pressure?
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The element that is dark-grey in colour at room temperature and pressure is D. iodine.
Step 5
Calculate the empirical formula of this tin chloride.
97%
117 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To calculate the empirical formula:
Convert grams to moles:
Moles of tin (Sn):
moles of Sn=119.0 g/mol1.199 g≈0.01008 moles
Moles of chlorine (Cl):
moles of Cl=35.5 g/mol1.429 g≈0.04024 moles
Find the smallest mole ratio:
Divide both by the smallest number of moles:
ratio of Sn=0.010080.01008=1ratio of Cl=0.010080.04024≈4
Empirical formula:
Based on the ratio, the empirical formula is SnCl₄.