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A student used the internet to find information about the percentages of different gases in the Earth’s early atmosphere - Edexcel - GCSE Chemistry - Question 1 - 2013 - Paper 1

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A student used the internet to find information about the percentages of different gases in the Earth’s early atmosphere. She was surprised to find the information g... show full transcript

Worked Solution & Example Answer:A student used the internet to find information about the percentages of different gases in the Earth’s early atmosphere - Edexcel - GCSE Chemistry - Question 1 - 2013 - Paper 1

Step 1

One of the gases in the table is present in a much larger amount in today's atmosphere. State the name of this gas.

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Answer

The gas present in a much larger amount in today's atmosphere is nitrogen.

Step 2

A gas not named in the table makes up about 21% of today's atmosphere. State the name of this gas.

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Answer

The gas that makes up about 21% of today's atmosphere is oxygen.

Step 3

Complete the sentence by putting a cross (✗) in the box next to your answer. The amount of carbon dioxide in the early atmosphere was reduced by

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Answer

D the gas dissolving in oceans.

Step 4

Explain why it is difficult to be certain about the composition of the Earth's early atmosphere.

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Answer

It is difficult to be certain about the composition of the Earth's early atmosphere because there were no humans to take measurements at that time. Additionally, the evidence or data we have about the composition mainly comes from ice core samples or rock data, which may not be old enough. Different sources can conflict, and websites may refer to different times or use varied interpretations, making it challenging to establish a clear picture.

Step 5

Calculate the percentage of oxygen in this sample of air.

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Answer

To find the percentage of oxygen in the air, we use the formula:

ext{Percentage of Oxygen} = rac{ ext{Initial Volume} - ext{Remaining Volume}}{ ext{Initial Volume}} imes 100

Inputting the values:

  • Initial Volume = 50 cm³
  • Remaining Volume = 41 cm³

ext{Percentage of Oxygen} = rac{50 - 41}{50} imes 100 = rac{9}{50} imes 100 = 18 ext{%}

Step 6

The word equation for the reaction is. Balance the equation for this reaction by putting numbers in the spaces provided.

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Answer

The balanced equation for the reaction is:

ightarrow ext{2 CuO}$$

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