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Calcium carbonate decomposes on heating to form calcium oxide and carbon dioxide - Edexcel - GCSE Chemistry - Question 4 - 2019 - Paper 1

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Calcium carbonate decomposes on heating to form calcium oxide and carbon dioxide. CaCO₃(s) → CaO(s) + CO₂(g). (a) 8.000g of CaCO₃ was heated strongly for about 10 ... show full transcript

Worked Solution & Example Answer:Calcium carbonate decomposes on heating to form calcium oxide and carbon dioxide - Edexcel - GCSE Chemistry - Question 4 - 2019 - Paper 1

Step 1

Calculate the mass of carbon dioxide gas given off.

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Answer

To calculate the mass of carbon dioxide gas given off, use the formula:

mass of CO2=initial mass of CaCO3−mass of solid remaining\text{mass of } CO_2 = \text{initial mass of } CaCO_3 - \text{mass of solid remaining} Given that the initial mass of calcium carbonate is 8.000g and the mass of solid remaining is 6.213g:

mass of CO2=8.000g−6.213g=1.787g\text{mass of } CO_2 = 8.000g - 6.213g = 1.787g

Thus, the mass of carbon dioxide gas given off is 1.787g.

Step 2

Calculate the percentage yield of calcium oxide.

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Answer

To find the percentage yield of calcium oxide, the formula is:

Percentage yield=(actual yieldtheoretical yield)×100\text{Percentage yield} = \left( \frac{\text{actual yield}}{\text{theoretical yield}} \right) \times 100 Where:

  • Actual yield = 5.450g (mass of calcium oxide remaining)
  • Theoretical yield = 5.600g

Substituting in the values:

Percentage yield=(5.450g5.600g)×100=97.32%\text{Percentage yield} = \left( \frac{5.450g}{5.600g} \right) \times 100 = 97.32\%

Thus, the percentage yield of calcium oxide is 97.32%.

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