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Copper hydroxide, copper oxide and copper sulfide are three compounds of copper - Edexcel - GCSE Chemistry - Question 4 - 2017 - Paper 1

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Copper hydroxide, copper oxide and copper sulfide are three compounds of copper. (a) (i) In solution copper chloride, CuCl₂, reacts with potassium hydroxide, KOH, ... show full transcript

Worked Solution & Example Answer:Copper hydroxide, copper oxide and copper sulfide are three compounds of copper - Edexcel - GCSE Chemistry - Question 4 - 2017 - Paper 1

Step 1

Write the balanced equation for this reaction.

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Answer

The balanced equation for the reaction between copper chloride and potassium hydroxide is:

CuCl2+2KOHCu(OH)2+2KClCuCl_2 + 2KOH \rightarrow Cu(OH)_2 + 2KCl

In this equation, the left-hand side (LHS) and right-hand side (RHS) are balanced with respect to the number of each type of atom.

Step 2

Which state symbol would be used in the equation to show that copper hydroxide is a precipitate?

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Answer

The state symbol to indicate a precipitate is (s) for solid. Thus, you would put a cross (✗) next to option C.

Step 3

Which of the following is the relative formula mass for copper hydroxide?

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Answer

To calculate the relative formula mass of Cu(OH)₂, we sum the atomic masses:

Relative mass=63.5+2(16)+1=97.5g/mol\text{Relative mass} = 63.5 + 2(16) + 1 = 97.5 \, \text{g/mol}

Thus, you would put a cross (✗) next to option C.

Step 4

Calculate the empirical formula of the copper sulfide.

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Answer

First, we need to determine the moles of copper and sulfur:

  1. Moles of copper:
Moles of Cu=12.7g63.5g/mol=0.2mol\text{Moles of Cu} = \frac{12.7 \, \text{g}}{63.5 \, \text{g/mol}} = 0.2 \, \text{mol}
  1. Moles of sulfur:
Moles of S=3.2g32g/mol=0.1mol\text{Moles of S} = \frac{3.2 \, \text{g}}{32 \, \text{g/mol}} = 0.1 \, \text{mol}
  1. The ratio of moles of Cu to S is:
Ratio=0.20.1=2:1\text{Ratio} = \frac{0.2}{0.1} = 2:1

Thus, the empirical formula of copper sulfide is Cu₂S.

Step 5

Calculate the maximum mass of copper oxide.

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Answer

To find the maximum mass of copper oxide (CuO) formed:

  1. Find moles of copper used:
Moles of Cu=25.4g63.5g/mol0.4mol\text{Moles of Cu} = \frac{25.4 \, \text{g}}{63.5 \, \text{g/mol}} \approx 0.4 \, \text{mol}
  1. From the equation 2Cu + O₂ → 2CuO, 2 moles of Cu produce 2 moles of CuO. Therefore:
Moles of CuO=0.4mol\text{Moles of CuO} = 0.4 \, \text{mol}
  1. Calculate the mass of CuO:
Mass of CuO=0.4mol×79.5g/mol=31.8g\text{Mass of CuO} = 0.4 \, \text{mol} \times 79.5 \, \text{g/mol} = 31.8 \, \text{g}

Thus, the maximum mass of copper oxide that can be formed is approximately 31.8 g.

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