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Sucrose is a carbohydrate - Edexcel - GCSE Chemistry - Question 4 - 2022 - Paper 1

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Sucrose is a carbohydrate. When a solution of sucrose is fermented using yeast, ethanol is formed. sucrose + water ⇌ ethanol + carbon dioxide In one experiment, ... show full transcript

Worked Solution & Example Answer:Sucrose is a carbohydrate - Edexcel - GCSE Chemistry - Question 4 - 2022 - Paper 1

Step 1

State the meanings of the terms actual yield and theoretical yield.

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Answer

The actual yield refers to the mass of product obtained from a reaction after it has been completed. This can vary due to various factors like inefficiencies in the reaction process or side reactions.
The theoretical yield, on the other hand, is the maximum mass of product that could be formed based on stoichiometric calculations, assuming complete conversion of reactants under ideal conditions.

Step 2

Use the information in Figure 3 to calculate the percentage yield of ethanol in this experiment.

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Answer

To calculate the percentage yield of ethanol, we use the formula:

extpercentageyield=(actual yieldtheoretical yield)×100 ext{percentage yield} = \left( \frac{\text{actual yield}}{\text{theoretical yield}} \right) \times 100

Substituting the values from Figure 3:

percentage yield=(8.0753.80)×10015.00%\text{percentage yield} = \left( \frac{8.07}{53.80} \right) \times 100 \approx 15.00 \%

Step 3

State two reasons why the actual yield of a reaction is usually less than the theoretical yield.

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Answer

  1. Some reactants may remain unreacted due to incomplete reactions.
  2. Side reactions may occur, leading to products that are not the desired outcome, which decreases the overall yield.

Step 4

Calculate the atom economy of this reaction to produce ethanol.

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Answer

To calculate the atom economy, we use the formula:

extatomeconomy=(mass of desired producttotal mass of reactants)×100 ext{atom economy} = \left( \frac{\text{mass of desired product}}{\text{total mass of reactants}} \right) \times 100

Where:

  • Mass of desired product (ethanol) = 4 × 46 g = 184 g
  • Total mass of reactants = 342 g (C₁₂H₂₁O₁₁) + 18 g (H₂O) = 360 g

Thus,

extatomeconomy=(184360)×10051.11% ext{atom economy} = \left( \frac{184}{360} \right) \times 100 \approx 51.11 \%

To two significant figures, the atom economy is 51%.

Step 5

Explain the effect on the atom economy of this reaction if the carbon dioxide produced was used to make fizzy drinks.

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Answer

If the carbon dioxide produced during the fermentation reaction was repurposed for making fizzy drinks, the effective output from the reaction would increase. This would mean a higher utilization of all products formed, boosting the atom economy since more product is being used beneficially, thus increasing the overall efficiency of the reaction.

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