Photo AI

A student carried out a flame test on a sample of solid potassium chloride - Edexcel - GCSE Chemistry - Question 10 - 2023 - Paper 2

Question icon

Question 10

A-student-carried-out-a-flame-test-on-a-sample-of-solid-potassium-chloride-Edexcel-GCSE Chemistry-Question 10-2023-Paper 2.png

A student carried out a flame test on a sample of solid potassium chloride. The student followed this method. step 1 dip a dry wooden splint into water step 2 then... show full transcript

Worked Solution & Example Answer:A student carried out a flame test on a sample of solid potassium chloride - Edexcel - GCSE Chemistry - Question 10 - 2023 - Paper 2

Step 1

Explain one improvement that the student could make to their method to obtain a valid conclusion.

96%

114 rated

Answer

One improvement that the student could make is to use a clean wooden splint for each test. This would prevent contamination from any previous tests, ensuring that the results are accurate and reflective of the sample being tested.

Step 2

What colour should the student have seen in the flame if the test had been carried out correctly?

99%

104 rated

Answer

The student should have seen a lilac colour (Option B) in the flame if the test had been carried out correctly, as potassium ions produce this distinctive colour during a flame test.

Step 3

Describe the test for chloride ions.

96%

101 rated

Answer

To test for chloride ions, a small amount of the sample is dissolved in water to create a solution. Then, a few drops of dilute nitric acid followed by a few drops of silver nitrate solution are added. If chloride ions are present, a white precipitate of silver chloride will form.

Step 4

Calculate the mass of barium chloride that must be dissolved in water to make 25 cm³ of solution of this concentration.

98%

120 rated

Answer

To find the mass of barium chloride needed, we can use the formula:

Mass = Concentration × Volume.

Firstly, convert the volume from cm³ to dm³:

25 cm³ = 0.025 dm³.

Now, using the concentration of 83 g dm⁻³:
Mass = 83 g dm⁻³ × 0.025 dm³ = 2.075 g.

Rounding to 2 significant figures, the mass of barium chloride required is approximately 2.1 g.

Step 5

Write the ionic equation for this reaction.

97%

117 rated

Answer

The ionic equation for the reaction between barium chloride and aluminium sulfate is:

3Ba2+(aq)+3SO42(aq)+2Al3+(aq)+6Cl(aq)3BaSO4(s)+2Al3+(aq)+6Cl(aq)3Ba^{2+}(aq) + 3SO_4^{2-}(aq) + 2Al^{3+}(aq) + 6Cl^{-}(aq) \rightarrow 3BaSO_4(s) + 2Al^{3+}(aq) + 6Cl^{-}(aq)

This shows the formation of a barium sulfate precipitate.

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;