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(a) (i) Ethanoic acid, CH₃COOH, reacts with ethanol to form ethyl ethanoate and water - Edexcel - GCSE Chemistry - Question 5 - 2016 - Paper 1

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(a) (i) Ethanoic acid, CH₃COOH, reacts with ethanol to form ethyl ethanoate and water. Complete the equation for the reaction by adding the formula of ethyl ethanoa... show full transcript

Worked Solution & Example Answer:(a) (i) Ethanoic acid, CH₃COOH, reacts with ethanol to form ethyl ethanoate and water - Edexcel - GCSE Chemistry - Question 5 - 2016 - Paper 1

Step 1

(i) Complete the equation for the reaction by adding the formula of ethyl ethanoate.

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Answer

To complete the equation for the reaction between ethanoic acid and ethanol to form ethyl ethanoate and water, we can write:

CH3COOH+C2H5OHCH3COOC2H5+H2OCH₃COOH + C₂H₅OH \rightarrow CH₃COOC₂H₅ + H₂O

Here, ethyl ethanoate is represented as CH₃COOC₂H₅.

Step 2

(ii) State what you would see if solid calcium carbonate is added to some dilute ethanoic acid.

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Answer

When solid calcium carbonate (CaCO₃) is added to dilute ethanoic acid, you would see effervescence, which includes fizzing or bubbling. This occurs because the reaction produces carbon dioxide gas as one of the products, leading to the observable release of bubbles. Additionally, the solid may appear to dissolve.

Step 3

(b) Complete the sentence by putting a cross (✗) in the box next to your answer.

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Answer

To find the concentration of ethanoic acid, we use the formula:

extConcentration(moldm3ext)=extNumberofmolesextVolume(dm3ext) ext{Concentration (mol dm}^{-3} ext{)} = \frac{ ext{Number of moles}}{ ext{Volume (dm}^{3} ext{)}}

First, calculate the number of moles:

extNumberofmoles=mass (g)molar mass (g mol1)=6.060=0.1extmol ext{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g mol}^{-1}\text{)}} = \frac{6.0}{60} = 0.1 ext{ mol}

Now, as the volume is 1.0 dm³:

extConcentration=0.1extmol1.0extdm3=0.1extmoldm3 ext{Concentration} = \frac{0.1 ext{ mol}}{1.0 ext{ dm}^3} = 0.1 ext{ mol dm}^{-3}

Thus, the correct answer is A 0.1.

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