Calculate the relative formula mass of calcium carbonate, CaCO₃ - Edexcel - GCSE Chemistry - Question 4 - 2016 - Paper 1
Question 4
Calculate the relative formula mass of calcium carbonate, CaCO₃.
(relative atomic masses: C = 12, O = 16, Ca = 40)
Magnesium reacts with sulfur to form magnesium su... show full transcript
Worked Solution & Example Answer:Calculate the relative formula mass of calcium carbonate, CaCO₃ - Edexcel - GCSE Chemistry - Question 4 - 2016 - Paper 1
Step 1
Calculate the relative formula mass of calcium carbonate, CaCO₃.
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Answer
To calculate the relative formula mass of calcium carbonate (CaCO₃), we sum the relative atomic masses of each element in the compound:
Calcium (Ca): 40 g/mol
Carbon (C): 12 g/mol
Oxygen (O): 16 g/mol, and there are 3 oxygen atoms. Therefore:
Thus, the relative formula mass of CaCO₃ is 100 g/mol.
Step 2
The ratio of magnesium atoms to sulfur atoms in magnesium sulfide is
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In magnesium sulfide (MgS), the molar mass of magnesium (Mg) is 24 g/mol and sulfur (S) is 32 g/mol. From the combination:
24 g of magnesium contains 1 mole of Mg.
32 g of sulfur contains 1 mole of S.
Therefore, the ratio of magnesium atoms to sulfur atoms is:
extRatio=1:1
Step 3
Give the empirical formula of aluminium oxide.
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Answer
The simplest ratio of aluminium atoms to oxygen atoms in aluminium oxide is given as 2 : 3. Thus, the empirical formula of aluminium oxide can be represented as:
extEmpiricalFormula=extAl2extO3
Step 4
What is the molecular formula of the hydrocarbon with the empirical formula CH₂?
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The molecular formula can be determined by examining the given empirical formula (CH₂). Hydrocarbons with CH₂ as the empirical formula could have molecular formulas such as C₂H₄ (ethene) or C₃H₆ (propene). Therefore, the molecular formula options are:
A (C₄H₈)
B (C₂H₄)
C (C₃H₆)
D (C₄H₈)
The correct answer is C₂H₄, which can be marked with a cross (🗹).
Step 5
Calculate the percentage yield of zinc oxide.
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The percentage yield is calculated using the formula:
Explain why the actual yield of a product in an experiment is usually lower than the theoretical yield.
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The actual yield of a product is often lower than the theoretical yield due to several factors:
Incomplete Reactions: Not all reactants may have reacted, leading to less product formation.
Side Reactions: Other unwanted chemical reactions may occur, producing by-products instead of the desired product.
Loss of Product: Some product may be lost during the transfer or purification processes, which lowers the measured yield.
Step 7
Calculate the percentage by mass of zinc in zinc oxide, ZnO.
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To find the percentage by mass of zinc in zinc oxide (ZnO), we first need to determine the molar mass of ZnO:
Zinc (Zn): 65 g/mol
Oxygen (O): 16 g/mol
Total molar mass of ZnO:
extMolarMassofZnO=65+16=81extg/mol
The percentage by mass of zinc is given by:
ext{Percentage by Mass of Zn} = rac{ ext{Molar Mass of Zn}}{ ext{Molar Mass of ZnO}} imes 100 = rac{65}{81} imes 100 \\approx 80.25 ext{ %}