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Question 9
A student carried out an investigation to determine the order of reactivity of four metals, W, X, Y, and Z. A piece of metal W was added to a test tube containing e... show full transcript
Step 1
Answer
The order of reactivity from least to most reactive is:
X - Y - W - Z
This is deduced from the observations where metal X showed very little reaction, metal Y reacted quickly, metal W reacted quickly with some remaining metal after three minutes, and metal Z completed the reaction fully.
Step 2
Answer
The reaction between metal Y and dilute sulfuric acid stopped because the metal Y likely formed a protective layer of sulfate or similar compound on its surface, which prevented further reaction with the acid. This passivation occurs when the surface of the metal becomes coated, stopping additional oxidation and hydrogen gas production.
Step 3
Answer
A weak acid is one that does not completely dissociate into ions in solution. In contrast to strong acids, which fully ionize and release protons (H⁺) into the solution, weak acids only partially dissociate, resulting in a lower concentration of hydrogen ions. This means weak acids are less effective at donating protons and thus have a smaller effect on the pH of solutions.
Step 4
Answer
First, determine the formula mass of Al₂(SO₄)₃:
Next, find the number of moles in 5.13 g of Al₂(SO₄)₃: Moles = mass / molar mass = 5.13 g / 342.0 g/mol = 0.0150 mol
The total number of atoms in Al₂(SO₄)₃:
Total number of atoms = 0.0150 mol x 17 atoms/formula unit x 6.02 x 10²³ atoms/mol = 1.53 x 10²² atoms.
Step 5
Answer
From the data given: 4.48 g of iron = 4.48 g / 56.0 g/mol = 0.0800 mol of Fe. According to the equations:
For Equation 1: 1 mol of Fe reacts with 1 mol of Pb, hence 0.0800 mol of Fe should produce 0.0800 mol of Pb. Total mass of Pb produced = 0.0800 mol x 207 g/mol = 16.56 g.
For Equation 2: 2 mol of Fe produces 3 mol of Pb. Thus, 0.0800 mol of Fe will produce (3/2) * 0.0800 mol = 0.1200 mol of Pb. Total mass of Pb produced = 0.1200 mol x 207 g/mol = 24.84 g.
Thus, Equation 2 represents the reaction taking place.
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