Photo AI

6 (a) Methane is a hydrocarbon fuel - Edexcel - GCSE Chemistry - Question 6 - 2020 - Paper 1

Question icon

Question 6

6-(a)-Methane-is-a-hydrocarbon-fuel-Edexcel-GCSE Chemistry-Question 6-2020-Paper 1.png

6 (a) Methane is a hydrocarbon fuel. (i) Complete the word equation for the complete combustion of methane in oxygen. methane + oxygen → water (ii) The incomplete... show full transcript

Worked Solution & Example Answer:6 (a) Methane is a hydrocarbon fuel - Edexcel - GCSE Chemistry - Question 6 - 2020 - Paper 1

Step 1

Complete the word equation for the complete combustion of methane in oxygen.

96%

114 rated

Answer

The complete word equation for the combustion of methane in oxygen is:

methane + oxygen → water

Step 2

Give the reason why carbon and carbon monoxide are produced in the incomplete combustion of methane.

99%

104 rated

Answer

Carbon and carbon monoxide are produced in the incomplete combustion of methane due to a limited supply of oxygen. When oxygen is insufficient, the methane does not fully react and thus forms these by-products.

Step 3

Name the fraction in Figure 10 that is used to surface roads.

96%

101 rated

Answer

The fraction used to surface roads is fuel oil.

Step 4

Name the fraction in Figure 10 that contains hydrocarbons with the lowest boiling point.

98%

120 rated

Answer

The fraction that contains hydrocarbons with the lowest boiling point is gases.

Step 5

Which of the following shows the fractions where the relative demand is greater than the relative amount in the crude oil?

97%

117 rated

Answer

The correct option is B: gases, petrol, diesel oil.

Step 6

Determine the value of x in the molecule of C₃H₈.

97%

121 rated

Answer

In the molecule of C₃H₈, x represents the number of hydrogen atoms. Therefore, x = 8.

Step 7

Calculate the maximum mass of octane that could be produced when 340g of dodecane is cracked in this reaction.

96%

114 rated

Answer

To find the maximum mass of octane, we first determine the number of moles of dodecane:

[ \text{moles of dodecane} = \frac{340\ g}{170\ g/mol} = 2\ mol ]

Since 1 mole of dodecane produces 1 mole of octane, the maximum moles of octane produced is also 2 moles. Then, we calculate the mass of octane produced:

[ \text{mass of octane} = 2\ mol \times 114\ g/mol = 228\ g ]

Thus, the maximum mass of octane that can be produced is 228 g.

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;