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The diagram shows a right-angled triangle and a quarter circle - Edexcel - GCSE Maths - Question 10 - 2020 - Paper 2

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The diagram shows a right-angled triangle and a quarter circle. The right-angled triangle ABC has angle ABC = 90° The quarter circle has centre C and radius CB. Wo... show full transcript

Worked Solution & Example Answer:The diagram shows a right-angled triangle and a quarter circle - Edexcel - GCSE Maths - Question 10 - 2020 - Paper 2

Step 1

Work out the length of CB

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Answer

To find the length of radius CB, we can use the Pythagorean theorem, as triangle ABC is a right-angled triangle.

Using the formula: a2+b2=c2a^2 + b^2 = c^2 where (a = 6 \text{ m} ) and (b = 9 \text{ m} ), the length of CB (hypotenuse) will be:

CB=(62+92)=36+81=11710.817 mCB = \sqrt{(6^2 + 9^2)} = \sqrt{36 + 81} = \sqrt{117} \approx 10.817 \text{ m}

Step 2

Calculate the area of the quarter circle

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Answer

The area of a quarter circle is given by the formula:

Area=14πr2\text{Area} = \frac{1}{4} \pi r^2

Substituting the radius we found:

Area=14π(10.817)214π(116.939)92.201 m2\text{Area} = \frac{1}{4} \pi (10.817)^2 \approx \frac{1}{4} \pi (116.939) \approx 92.201 \text{ m}^2

Finally, rounding to 3 significant figures, the area is approximately:

(92.2 ext{ m}^2)

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