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Show that \( (x + 1)(x + 2)(x + 3) \) can be written in the form \( ax^3 + bx^2 + cx + d \) where a, b, c and d are positive integers. - Edexcel - GCSE Maths - Question 10 - 2017 - Paper 1

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Question 10

Show-that-\(-(x-+-1)(x-+-2)(x-+-3)-\)-can-be-written-in-the-form-\(-ax^3-+-bx^2-+-cx-+-d-\)-where-a,-b,-c-and-d-are-positive-integers.-Edexcel-GCSE Maths-Question 10-2017-Paper 1.png

Show that \( (x + 1)(x + 2)(x + 3) \) can be written in the form \( ax^3 + bx^2 + cx + d \) where a, b, c and d are positive integers.

Worked Solution & Example Answer:Show that \( (x + 1)(x + 2)(x + 3) \) can be written in the form \( ax^3 + bx^2 + cx + d \) where a, b, c and d are positive integers. - Edexcel - GCSE Maths - Question 10 - 2017 - Paper 1

Step 1

Step 1: Expand the Expression

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Answer

To show that ( (x + 1)(x + 2)(x + 3) ) can be expressed as ( ax^3 + bx^2 + cx + d ), we first need to expand the expression. We can do this by multiplying two of the factors first:

[ (x + 1)(x + 2) = x^2 + 2x + 1x + 2 = x^2 + 3x + 2 ]

Next, we will multiply this result by the remaining factor ( (x + 3) ):

[ (x^2 + 3x + 2)(x + 3) = x^3 + 3x^2 + 3x^2 + 9x + 2x + 6 = x^3 + 6x^2 + 11x + 6 ]

Step 2

Step 2: Identify Coefficients a, b, c, d

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Answer

From the expanded polynomial ( x^3 + 6x^2 + 11x + 6 ), we can identify the coefficients:

  • ( a = 1 )
  • ( b = 6 )
  • ( c = 11 )
  • ( d = 6 )

Since all coefficients ( a, b, c, d ) are positive integers, we can conclude that the given expression can indeed be represented in the required form.

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