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Question 17
ABC and ADC are triangles. The area of triangle ADC is 56 m² Work out the length of AB. Give your answer correct to 1 decimal place.
Step 1
Answer
We know that the area of triangle ADC is given by:
ext{Area} = rac{1}{2} imes ext{base} imes ext{height}Here, the base can be AC, and we know the area is 56 m². We need to find the height corresponding to AC.
To find the height, we can use the angle opposite to AC, which is 105°. So,
Setting the area equation:
56 = rac{1}{2} imes AC imes (AC imes an(105°))This gives:
56 = rac{1}{2} imes AC^2 imes an(105°)Solving for AC, we first need the value of ( an(105°) \approx -0.9657 ):
AC^2 = rac{56 imes 2}{-0.9657}Calculating gives us AC.
Step 2
Answer
We can now use the Law of Sines to find AB. In triangle ABC:
rac{AB}{ ext{sin}(48°)} = rac{AC}{ ext{sin}(118°)}From step 1, we calculated the value of AC. Plugging that into the equation gives:
AB = rac{AC imes ext{sin}(48°)}{ ext{sin}(118°)}Calculating AB will give us the required length.
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