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Question 13
(ax^n)^{1/3} = 7x^2 Work out the value of a and the value of n.
Step 1
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Answer
To find the value of a, we need to rewrite the equation. First, we raise both sides to the power of 3:
(axn)=(7x2)3(ax^n) = (7x^2)^3(axn)=(7x2)3
Calculating the right side gives:
73x2∗3=343x67^3 x^{2*3} = 343x^673x2∗3=343x6
This means we must have:
axn=343x6ax^n = 343x^6axn=343x6
From this equality, we can deduce that:
a = 343\ Thus, the value of a is 343.
Step 2
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Continuing from our previous equation:
Since the bases of x are the same, we can compare the exponents. Therefore:
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