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The histogram gives information about the distribution of the weights of some onions grown by a farmer - Edexcel - GCSE Maths - Question 22 - 2019 - Paper 3

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The histogram gives information about the distribution of the weights of some onions grown by a farmer. Onions less than 60 grams in weight are used for pickling. O... show full transcript

Worked Solution & Example Answer:The histogram gives information about the distribution of the weights of some onions grown by a farmer - Edexcel - GCSE Maths - Question 22 - 2019 - Paper 3

Step 1

Find the total frequency

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Answer

To determine the total frequency from the histogram, we need to calculate the area of each bar:

  • From 0 to 60 grams: area = height (5) x width (60) = 300
  • From 60 to 90 grams: area = height (9) x width (30) = 270
  • From 90 to 120 grams: area = height (10) x width (30) = 300
  • From 120 to 180 grams: area = height (4) x width (60) = 240

Now, summing these areas gives:

Total frequency = 300 + 270 + 300 + 240 = 1110.

Step 2

Calculate the number of onions used for pickling

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Answer

Onions less than 60 grams (5 frequency density) represent:

Number of onions = height (5) x width (60) = 300.

Thus, 300 onions are used for pickling.

Step 3

Calculate the number of onions sold at the market

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Answer

Onions greater than 120 grams can be computed from the histogram:

  • From 120 to 180 grams: area = 240 (height 4, width 60)

Thus, number of onions sold at the market = 240.

Step 4

Determine the number of onions sent to the food processing factory

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Answer

The remaining onions can be determined by subtracting the quantities used for pickling and sold:

Total onions = 1110 - (300 for pickling + 240 sold) = 570 onions sent to the food processing factory.

To find the angle xx^\circ of the sector for the food processing factory:

Angle = 5701110×360=185.45\frac{570}{1110} \times 360 = 185.45^\circ.

Rounding to the nearest degree gives: x=185x = 185.

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