1. Let $ar{E} = \{ \text{even numbers between 1 and 25} \}$
$A = \{ 2, 8, 10, 14 \}$
$B = \{ 6, 8, 20 \}$
$C = \{ 6, 18, 20, 22 \}$
(a) Complete the Venn diagram for this information - Edexcel - GCSE Maths - Question 3 - 2018 - Paper 2
Question 3
1. Let $ar{E} = \{ \text{even numbers between 1 and 25} \}$
$A = \{ 2, 8, 10, 14 \}$
$B = \{ 6, 8, 20 \}$
$C = \{ 6, 18, 20, 22 \}$
(a) Complete the Ve... show full transcript
Worked Solution & Example Answer:1. Let $ar{E} = \{ \text{even numbers between 1 and 25} \}$
$A = \{ 2, 8, 10, 14 \}$
$B = \{ 6, 8, 20 \}$
$C = \{ 6, 18, 20, 22 \}$
(a) Complete the Venn diagram for this information - Edexcel - GCSE Maths - Question 3 - 2018 - Paper 2
Step 1
Complete the Venn diagram for this information.
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Answer
To complete the Venn diagram, we first need to identify the numbers in each set:
Set A contains: 2, 8, 10, 14
Set B contains: 6, 8, 20
Set C contains: 6, 18, 20, 22
Now let's determine the overlaps:
A and B: The common number is 8.
A and C: There are no common numbers.
B and C: The common numbers are 6 and 20.
A, B, and C: There are no common numbers among all three sets.
The completed Venn diagram should have:
In circle A: 2, 10, 14 (with 8 in the overlap with B)
In circle B: 6 (with 8 in the overlap with A and 20 in the overlap with C)
In circle C: 18, 22 (with 6 and 20 in overlaps with B)
The central region where all three overlap is empty.
Thus, the completed Venn diagram shows the numbers positioned correctly based on their memberships in the respective sets.
Step 2
Find the probability that the number is a member of A ∩ B.
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Answer
To calculate the probability that a randomly chosen number from ar{E} is a member of A∩B:
Identify members of A∩B: The only member common to both A and B is 8.
Determine the total number of even numbers in ar{E}: The even numbers between 1 and 25 are 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24. This gives us a total of 12 even numbers.
Calculate the probability: The probability P that a number is in A∩B is calculated as:
P(A∩B)=Total number of elements in EˉNumber of elements in A∩B=121