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Sakira invested £3550 in a savings account for 3 years - Edexcel - GCSE Maths - Question 14 - 2019 - Paper 2

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Sakira invested £3550 in a savings account for 3 years. She was paid 2.6% per annum compound interest for each of the first 2 years. She was paid R% interest for th... show full transcript

Worked Solution & Example Answer:Sakira invested £3550 in a savings account for 3 years - Edexcel - GCSE Maths - Question 14 - 2019 - Paper 2

Step 1

Calculate the total amount after 2 years at 2.6% interest

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Answer

To calculate the amount after 2 years of compound interest, use the formula: A=P(1+r)nA = P(1 + r)^n Where:

  • A = final amount
  • P = principal amount (£3550)
  • r = interest rate per year (2.6% = 0.026)
  • n = number of years (2)

Substituting in the values, we have: A=3550(1+0.026)2=3550(1.026)23550(1.052676)3735.07A = 3550(1 + 0.026)^2 = 3550(1.026)^2 \approx 3550(1.052676) \approx 3735.07 Thus, after 2 years, the total amount in the account is approximately £3735.07.

Step 2

Calculate the amount of interest earned in the third year at R%

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Answer

After 2 years, the amount is £3735.07. To find R%, we first set the final amount after 3 years equal to the total amount received:

Let the interest earned in the third year be: I3=3735.07×R100I_3 = 3735.07 \times \frac{R}{100}

The final amount is given as £3819.21. Therefore: 3735.07+I3=3819.213735.07 + I_3 = 3819.21 This implies: I3=3819.213735.07=84.14I_3 = 3819.21 - 3735.07 = 84.14

Substituting back into our interest formula: 84.14=3735.07×R10084.14 = 3735.07 \times \frac{R}{100}

Solving for R gives: R=84.14×1003735.072.25R = \frac{84.14 \times 100}{3735.07} \approx 2.25 Thus, the value of R is approximately 2.2% when rounded to one decimal place.

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