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Show that $(x + 1)(x + 2)(x + 3)$ can be written in the form $ax^3 + bx^2 + cx + d$ where $a$, $b$, $c$ and $d$ are positive integers. - Edexcel - GCSE Maths - Question 10 - 2017 - Paper 1

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Question 10

Show-that--$(x-+-1)(x-+-2)(x-+-3)$-can-be-written-in-the-form-$ax^3-+-bx^2-+-cx-+-d$-where-$a$,-$b$,-$c$-and-$d$-are-positive-integers.-Edexcel-GCSE Maths-Question 10-2017-Paper 1.png

Show that $(x + 1)(x + 2)(x + 3)$ can be written in the form $ax^3 + bx^2 + cx + d$ where $a$, $b$, $c$ and $d$ are positive integers.

Worked Solution & Example Answer:Show that $(x + 1)(x + 2)(x + 3)$ can be written in the form $ax^3 + bx^2 + cx + d$ where $a$, $b$, $c$ and $d$ are positive integers. - Edexcel - GCSE Maths - Question 10 - 2017 - Paper 1

Step 1

Step 1: Expand the product

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Answer

To show that (x+1)(x+2)(x+3)(x + 1)(x + 2)(x + 3) can be expressed in the desired form, we first expand the product. We can group the factors as follows:

  1. First multiply the first two factors: (x+1)(x+2)=x2+2x+x+2=x2+3x+2(x + 1)(x + 2) = x^2 + 2x + x + 2 = x^2 + 3x + 2

  2. Next, multiply this result by the third factor: (x2+3x+2)(x+3)(x^2 + 3x + 2)(x + 3)

Step 2

Step 2: Complete the multiplication

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Answer

We will distribute each term in (x2+3x+2)(x^2 + 3x + 2) by (x+3)(x + 3):

  • Multiply x2x^2 by (x+3)(x + 3): x2imes(x+3)=x3+3x2x^2 imes (x + 3) = x^3 + 3x^2
  • Multiply 3x3x by (x+3)(x + 3): 3ximes(x+3)=3x2+9x3x imes (x + 3) = 3x^2 + 9x
  • Multiply 22 by (x+3)(x + 3): 2imes(x+3)=2x+62 imes (x + 3) = 2x + 6

Combining all these terms gives: x3+3x2+3x2+9x+2x+6x^3 + 3x^2 + 3x^2 + 9x + 2x + 6

Step 3

Step 3: Simplify the expression

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Answer

Now we combine like terms: x3+(3x2+3x2)+(9x+2x)+6x^3 + (3x^2 + 3x^2) + (9x + 2x) + 6 This simplifies to: x3+6x2+11x+6x^3 + 6x^2 + 11x + 6 This is now in the form ax3+bx2+cx+dax^3 + bx^2 + cx + d, where:

  • a=1a = 1
  • b=6b = 6
  • c=11c = 11
  • d=6d = 6 Since all coefficients are positive integers, we have successfully shown that the expression can be represented in the required form.

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