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Here are the first five terms of an arithmetic sequence - Edexcel - GCSE Maths - Question 3 - 2022 - Paper 2

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Here are the first five terms of an arithmetic sequence. 7 13 19 25 31 (a) Find an expression, in terms of n, for the nth term of this sequence. The nth term ... show full transcript

Worked Solution & Example Answer:Here are the first five terms of an arithmetic sequence - Edexcel - GCSE Maths - Question 3 - 2022 - Paper 2

Step 1

Find an expression, in terms of n, for the nth term of this sequence.

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Answer

The given terms form an arithmetic sequence. The first term (a) is 7 and the common difference (d) is found by subtracting the first term from the second term:

d=137=6d = 13 - 7 = 6

The nth term of an arithmetic sequence can be expressed as:

Tn=a+(n1)dT_n = a + (n - 1)d

Substituting the values of a and d:

Tn=7+(n1)6T_n = 7 + (n - 1)6

Simplifying this gives:

Tn=7+6n6=6n+1T_n = 7 + 6n - 6 = 6n + 1

Thus, the expression for the nth term is: Tn=6n+1T_n = 6n + 1

Step 2

Is -58 a term of this sequence?

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Answer

To determine if -58 is a term of the sequence, we set the nth term equal to -58:

6n+1=586n + 1 = -58

Subtracting 1 from both sides:

6n=596n = -59

Dividing both sides by 6 gives:

n=596n = -\frac{59}{6}

Since n must be a positive integer, -58 is not a term of this sequence.

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