Kiaria is 7 years older than Jay - Edexcel - GCSE Maths - Question 2 - 2017 - Paper 1

Next, we represent Martha's age, which is twice that of Kiaria: $m = 2k$ Substituting Kiaria's age, we get: $m = 2(j + 7)$

Given that the sum of their ages is 77, we can formulate the equation: $j + k + m = 77$ Substituting the expressions we found: $j + (j + 7) + 2(j + 7) = 77$

Combine like terms to simplify the equation: $j + j + 7 + 2j + 14 = 77$ This simplifies to: $4j + 21 = 77$ Subtracting 21 from both sides gives: $4j = 56$ Thus, dividing by 4 results in: $j = 14$

Using Jay’s age, we can find Kiaria's age: $k = j + 7 = 14 + 7 = 21$ And then for Martha: $m = 2k = 2 imes 21 = 42$

Finally, to find the ratio of Jay's age to Kiaria's age to Martha's age, we write: $ext{Ratio} = j:k:m = 14:21:42$ Simplifying the ratio by dividing each term by 7 gives: $ext{Ratio} = 2:3:6$