Photo AI

2 $v^2 = u^2 + 2as$ $u = 12, a = -3, s = 18$ (a) Work out a value of $v$ - Edexcel - GCSE Maths - Question 3 - 2018 - Paper 1

Question icon

Question 3

2--$v^2-=-u^2-+-2as$--$u-=-12,-a-=--3,-s-=-18$--(a)-Work-out-a-value-of-$v$-Edexcel-GCSE Maths-Question 3-2018-Paper 1.png

2 $v^2 = u^2 + 2as$ $u = 12, a = -3, s = 18$ (a) Work out a value of $v$. (b) Make $s$ the subject of $v^2 = u^2 + 2as$

Worked Solution & Example Answer:2 $v^2 = u^2 + 2as$ $u = 12, a = -3, s = 18$ (a) Work out a value of $v$ - Edexcel - GCSE Maths - Question 3 - 2018 - Paper 1

Step 1

(a) Work out a value of v.

96%

114 rated

Answer

To find the value of vv, we will substitute the given values into the equation:

  1. Start with the equation: v2=u2+2asv^2 = u^2 + 2as

  2. Substitute the values: u=12,a=3,s=18u = 12, a = -3, s = 18

    Thus, we have: v2=122+2(3)(18)v^2 = 12^2 + 2(-3)(18)

  3. Calculate the terms: v2=144+2(3)(18)v^2 = 144 + 2(-3)(18) v2=144108v^2 = 144 - 108 v2=36v^2 = 36

  4. Finally, take the square root to solve for vv: v=extsqrt(36)=6v = ext{sqrt}(36) = 6

Hence, the value of vv is 6.

Step 2

(b) Make s the subject of v^2 = u^2 + 2as

99%

104 rated

Answer

To make ss the subject of the equation, follow these steps:

  1. Start with the equation: v2=u2+2asv^2 = u^2 + 2as

  2. Rearrange to isolate ss: v2u2=2asv^2 - u^2 = 2as

  3. Divide both sides by 2a2a to solve for ss: s=v2u22as = \frac{v^2 - u^2}{2a}

Thus, the formula for ss as the subject is: s=v2u22as = \frac{v^2 - u^2}{2a}

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;