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1 (a) Work out $\frac{2}{7} + \frac{1}{4}$ (b) Work out $\frac{1}{5} - \frac{3}{4}$ Give your answer as a mixed number in its simplest form. - Edexcel - GCSE Maths - Question 1 - 2018 - Paper 1

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Question 1

1-(a)-Work-out-$\frac{2}{7}-+-\frac{1}{4}$--(b)-Work-out-$\frac{1}{5}---\frac{3}{4}$----Give-your-answer-as-a-mixed-number-in-its-simplest-form.-Edexcel-GCSE Maths-Question 1-2018-Paper 1.png

1 (a) Work out $\frac{2}{7} + \frac{1}{4}$ (b) Work out $\frac{1}{5} - \frac{3}{4}$ Give your answer as a mixed number in its simplest form.

Worked Solution & Example Answer:1 (a) Work out $\frac{2}{7} + \frac{1}{4}$ (b) Work out $\frac{1}{5} - \frac{3}{4}$ Give your answer as a mixed number in its simplest form. - Edexcel - GCSE Maths - Question 1 - 2018 - Paper 1

Step 1

Work out $\frac{2}{7} + \frac{1}{4}$

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Answer

To add the fractions 27\frac{2}{7} and 14\frac{1}{4}, we need a common denominator. The least common multiple of 7 and 4 is 28.

Convert each fraction:

27=2×47×4=828\frac{2}{7} = \frac{2 \times 4}{7 \times 4} = \frac{8}{28}

14=1×74×7=728\frac{1}{4} = \frac{1 \times 7}{4 \times 7} = \frac{7}{28}

Now add the two fractions:

828+728=1528\frac{8}{28} + \frac{7}{28} = \frac{15}{28}

Thus, the answer is 1528\frac{15}{28}.

Step 2

Work out $\frac{1}{5} - \frac{3}{4}$

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Answer

To subtract the fractions 15\frac{1}{5} and 34\frac{3}{4}, we again need a common denominator. The least common multiple of 5 and 4 is 20.

Convert each fraction:

15=1×45×4=420\frac{1}{5} = \frac{1 \times 4}{5 \times 4} = \frac{4}{20}

34=3×54×5=1520\frac{3}{4} = \frac{3 \times 5}{4 \times 5} = \frac{15}{20}

Now subtract the two fractions:

4201520=41520=1120\frac{4}{20} - \frac{15}{20} = \frac{4 - 15}{20} = \frac{-11}{20}

To express 1120\frac{-11}{20} as a mixed number, we note that it is less than 0 and cannot be expressed as a mixed number in positive terms. Thus, the result is 1120-\frac{11}{20}.

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