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ABCD is a parallelogram - Edexcel - GCSE Maths - Question 3 - 2017 - Paper 1

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ABCD is a parallelogram. EDC is a straight line. F is the point on AD so that BFE is a straight line. Angle EFD = 35° Angle DCB = 75° Show that angle ABF = 70° Give ... show full transcript

Worked Solution & Example Answer:ABCD is a parallelogram - Edexcel - GCSE Maths - Question 3 - 2017 - Paper 1

Step 1

Show that angle ABF = 70°

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Answer

  1. Since ABCD is a parallelogram, the opposite angles are equal. Therefore, angle DAB (which is equivalent to angle ABC) is equal to angle DCB, which is 75°.

  2. Angle EFD is given as 35°. Therefore, to find angle ABF, we can use the fact that angles on a straight line sum to 180°:

    180°35°=145°180° - 35° = 145°

  3. Now we know that angle DAB = 75°, and using the straight line relationship:

    ABF+DAB=145°ABF + DAB = 145°

    Substituting the known value:

    ABF+75°=145°ABF + 75° = 145°

  4. Thus, we can solve for angle ABF:

    ABF=145°75°=70°ABF = 145° - 75° = 70°

  5. Therefore, we have shown that angle ABF = 70°.

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