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ABC and EDC are straight lines - Edexcel - GCSE Maths - Question 5 - 2017 - Paper 2

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ABC and EDC are straight lines. E.A is parallel to D.B. EC = 8.1 cm. DC = 5.4 cm. DB = 2.6 cm. (a) Work out the length of AE. AC = 6.15 cm. (b) Work out the leng... show full transcript

Worked Solution & Example Answer:ABC and EDC are straight lines - Edexcel - GCSE Maths - Question 5 - 2017 - Paper 2

Step 1

(a) Work out the length of AE.

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Answer

To find the length of AE, we can use the property of similar triangles since E.A is parallel to D.B.

Using the ratio of the sides, we have:

AEEC=DBDC\frac{AE}{EC} = \frac{DB}{DC}

Plugging in the values:

AE8.1=2.65.4\frac{AE}{8.1} = \frac{2.6}{5.4}

Calculating the right side:

2.65.4=0.481\frac{2.6}{5.4} = 0.481

Thus, we have:

AE=8.1×0.481=3.9 cmAE = 8.1 \times 0.481 = 3.9 \text{ cm}

Step 2

(b) Work out the length of AB.

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Answer

To find the length of AB, we can again apply the property of similar triangles:

ABAC=ECDB\frac{AB}{AC} = \frac{EC}{DB}

Putting in the known measurements:

AB6.15=8.12.6\frac{AB}{6.15} = \frac{8.1}{2.6}

Calculating the right side:

8.12.63.115\frac{8.1}{2.6} \approx 3.115

Therefore:

AB=6.15×3.11519.217 cmAB = 6.15 \times 3.115 \approx 19.217 \text{ cm}

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